Answer:
Lauren wants to save 30% of her weekly paycheck. How much will she save each week if her paycheck is $150 a week?
1 answer:
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Answer:
Chandra's Average Monthly Expenses are;
1) For Both Jan and Feb are $269
2) For the remaining 10 months each are $244
Step-by-step explanation:
From Chandra's matrix all monthly expenses are all same that is,
Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.
That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.
Therefore, you start by adding up each month total expenses, which are ;
January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886
February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886
March = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
April = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
May = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
June = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
July= $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
August = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
September = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
October = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
November = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
December = $71 + $1,025 + $75 + $25 + $120 + $145 = $1461
Therefore Chandra's Average Monthly Expenses are:
1) January & February = =
= 269.4286 to the nearest cent
≅ $269
2) For the remaining 10 month are = =
= 243.5 to the nearest cent
≅ $244
Answer:
1a) p-hat=0.38
1b) P=0.08
1c) The null hypothesis is not rejected
2a) p-hat=0.64
2b) P=0.0027
2c) The null hypothesis is rejected
3a) p-hat=0.55
3b) P=0.153
3c) The null hypothesis is not rejected
Step-by-step explanation:
(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.
1a) The p-hat is p-hat=38/100=0.38.
1b) The standard deviation is
The sample size is n=100.
The z-value is:
As it is a two-sided test, the p-value considers both tails of the distribution.
The p-value for this |z|=1.74 is P=0.08.
1c) The null hypothesis is not rejected.
(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.
2a) The p-hat is p-hat=320/500=0.64.
2b) The standard deviation is
The sample size is n=500.
The z-value is:
As it is a two-sided test, the p-value considers both tails of the distribution.
The p-value for this |z|=3 is P=0.0027.
2c) The null hypothesis is rejected.
(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.
2a) The p-hat is p-hat=110/200=0.55.
2b) The standard deviation is
The sample size is n=200.
The z-value is:
As it is a two-sided test, the p-value considers both tails of the distribution.
The p-value for this |z|=1.43 is P=0.153.
2c) The null hypothesis is not rejected.