Answer:
64.3 lumens
Step-by-step explanation:
Data provided in the question:
Length of the testing chamber = 35 cm
Light at one end = 10 lumens
Light at other end = 200 lumens
now,
since the variation is linear,
therefore, the gradient of the variation
= 
= 5.43
also,
the darkest end is the end with 10 lumens
therefore,
The lumens at 10 cm from the darkest end
= 10 + 5.43(10)
= 10 + 54.3
= 64.3 lumens
Answer: z=0
Step-by-step explanation:
W=zr-2zt^3
Move all terms containing z to the left, all other terms to the right.
dd '-1rz' to each side of the equation.
-1rz+z=rz+-1rz+-2t^3z
Combine like terms: rz + -1rz = 0
-1rz+z=0+(-2t^3z)
-1rz+z=-2t^3z
Add 2t^3z to each side
-1rz+2t^3z+z=-2t^3z+2t^3z
Combine the like terms 2t^3z+2t^3z=0
-1rz+2t^3z+z=0
Factor out the Greatest Common Factor (GCF), 'z'.
z(-1r+2t^3+1)=0
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
First, simplify the (x+2)(x+2) with FOIL:
f(x)=(
)-3
Combine like terms
f(x)=
Then you have standard form.
Hope that helps.
A.) 14/15 B.) 17/14 C.) 5/12
Answer:
Step-by-step explanation:
hello :
sin x + 2 sin x cosx = 0 equivalent to : sinx(1+2cosx) =0
sinx=0 means : general solution is : x= kπ....k in Z
1+2cosx=0 means : cosx= -1/2 general solution is : x= ±π/6+kπ...k in Z
