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3 years ago

What percent of 965 is 1932

Mathematics

2 answers:

ankoles [38]3 years ago

4 0

Answer: It is 202.1 lol

Lena [83]3 years ago

4 0

The correct answer is 200.21%

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20c -18c=6 <br> Solve for c <br> C=

Leni [432]

Answer:

c=3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the slope of the line passing through the points (1, 2) and (5, 4)?

bulgar [2K]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

What is the slope of the line passing through the point (1,2) and (5,4)

$\Large\maltese\underline{\textsf{This problem has been solved!}}$

Formula used, here $\bf{\dfrac{y2-y1}{x2-x1}$

_______________________________________________________

$\bf{\dfrac{4-2}{5-1}$ | simplify

$\bf{\dfrac{2}{4}$ | reduce

$\bf{\dfrac{1}{2}$

$\rule{300}{1.7}$

$\bf{Result:}$

$\bf{=Slope:\dfrac{1}{2}$

$\boxed{\bf{aesthetic\not101}}$

3 0

2 years ago

Read 2 more answers

4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

2 years ago

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The average human body contains about 40 L of water. What is the total amount of water contained in the 6.4 billion people in th

vesna_86 [32]

Answer:

2.56 * 10^11 L

Step-by-step explanation:

1 body has 40 L

Thus, the amount in 6.4 billion would be;

40 * 6.4 * 10^9

= 256 * 10^9

= 2.56 * 10^2 * 10^9

= 2.56 * 10^11 L

7 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago