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2 years ago

What is another written expression for 5(x+5)

Mathematics

2 answers:

natima [27]2 years ago

8 0

Another written expression is 5x+25

Fantom [35]2 years ago

4 0

Answer:

5x+25

Step-by-step explanation:

5*x=5x

5*5=25

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I will give brainliest answer

snow_tiger [21]

Step-by-step explanation:

inner region

A=πr^2

A=π*6^2

A=π*36cm^2

A=113.09cm^2

shaded region(outer)

A=πr^2

A=π*9^2

A=π*81cm^2

A=254.46cm^2

Area of shaded region=254.46cm^2-113.09cm^2

=141.37cm^2

Mark brianliest if my answer suit your question

5 0

3 years ago

Read 2 more answers

Threatened monarch butterflies are monitored by measuring the area occupied by overwintering butterflies in Mexico. According to

Pani-rosa [81]

Answer:

14.2 hectares

Step-by-step explanation:

Fund Mexico, monarch butterflies occupied 1.13 hectares one recent winter, and 4.01 hectares the following winter (one year later)

The formula of Geometric growth

(Pt/ Po)^1/t

Where Pt = Size after t years = 4.01 hectares

Po = Initial size = 1.13

t = times = 1

=( 4.01/1.13 )^1/1

= 3.5486725664

Hence, Geometric growth rate = 3.5486725664.

It's size in hectares after another 1 year = Current size in hectares × Geometric growth rate

= 4.01 ×3.5486725664

= 14.230176991 hectares

≈ 14.2

6 0

2 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

2 years ago

Hi:) for triangle inequalities , the sum of two sides of a triangle has to be greater than the third side.

Jet001 [13]

Answer:

Step-by-step explanation:

Note :

Consider a triangle with sides‘s length a , b and c

triangle inequalities state that we must have c - a < b < c + a

now , is the third side always the longest ?

the answer is NO: (let’s take a counter example )

in a triangle with 2 sides‘s length 3 , 4

the third side could measure 2

because 4-3 < 2 < 4+3

8 0

2 years ago

If the bottom of a ship is 15.8 below the surface of the sea, calculate the pressure at the bottom of the ship. The density of t

Zolol [24]

Given:
Depth, h= 15.8
Density of seawater= 1030kg/m3

We need to find:
Pressure

Answer:
P= ρhg
P=(1030)(15.8)(9.81)= 159647.94 Pa

7 0

3 years ago