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Kisachek [45]
3 years ago
8

A circle with a diameter of 25 inches

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

A =πr2

Π  = 3.14

r = ½diameter = 25/2 =12.5 inches

∴ Area = 3.14 × 12.5 × 12.5 square inches

  Area = 490.625 square inches

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Evaluate each expression for the given value of the variables. 2x + y for x= 7 and y = 11​
prisoha [69]

Answer:

25

Step-by-step explanation:

Substitute 7 into 2, and 11 into y.

2(7)+(11)

14+11

25

4 0
3 years ago
A man drove his car a distance of 366 miles in 6 hours. If continuing at this rate is possible, he will travel ____ miles in 7 h
morpeh [17]

Ans

427

Step-by-step explanation:

divide 366 by 6 then multiply by 7.

5 0
3 years ago
Stan borrows $5,500 at a rate of 12% interest per year. What is the amount due at the end of 5 years if the interest is compound
kolbaska11 [484]
<span>Without compound interest, Stan would earn only $8,800.00. This means that thanks to the power of compound interest Stan will earn an additional $1,191.83 in interest at the end of the 5-year-term.</span>
7 0
3 years ago
Chi square Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, perc
Marat540 [252]

Answer:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

Step-by-step explanation:

The missing data for the random sample of 80 days between December and April with snowfall is:

 Month            Days

December         16

January             11

February            16

 March              18

  April                19

The Chi-square goodness of fit test would be used to determine whether the snow falls in Daphne's hometown followed the given distribution.

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The snow falls in Daphne's hometown does not follow the given distribution.

<em>Hₐ</em>: The snow falls in Daphne's hometown followed the given distribution.

Assume that the significance level of the test is, <em>α</em> = 0.05.

The Chi-square test statistic is given by:

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

The value of Chi-square test statistic is computed in the Excel sheet below.

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}=8.383

Compute the <em>p</em>-value as follows:

\text{p-value}=P(\chi^{2}_{(4)}>8.383)=CHISQ.DIST.RT(8.383,4)=0.0785

The <em>p</em>-value of the test is 0.0785.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

<em>p</em>-value = 0.0785 > <em>α</em> = 0.05.

The null hypothesis will not be rejected.

Conclusion:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

4 0
4 years ago
Convert .076 to a fraction
IgorC [24]
76/1000 because the place thousand and the number is 76

8 0
3 years ago
Read 2 more answers
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