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3 years ago

How to round to the nearest 10

2 answers:

6 0

Answer: If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.

cestrela7 [59]3 years ago

4 0

Answer:

Rounding decimals is very similar to rounding other numbers. If the hundredths and thousandths places of a decimal is forty-nine or less, they are dropped and the tenths place does not change.

Step-by-step explanation:

Example: rounding 0.813 to the nearest tenth would give 0.8

Example: rounding 0.572 to the nearest tenth would give 0.6

If the number is higher then 5 you will round up if it is lower it will stay the same

Hope this helps

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3 years ago

What is the solution set of the compound inequality x+1<-2x+11<3x+5

VikaD [51]

Answer:

6/5 < x < 10/3 is the desired solution.

Step-by-step explanation:

Here, the given compound inequality is :

x + 1 < -2 x + 11 < 3 x + 5

Now, consider the first two term of the inequality, we get:

x + 1 < -2 x + 11

Subtracting 1 from both sides, we get:

x + 1 - 1 < -2 x + 11 - 1

or, x < -2x + 10

or, x + 2x < 10

or, 3 x < 10

or, x < 10/3

Similarly, considering the last two terms of the given inequality, we get:

-2 x + 11 < 3 x + 5

Subtracting 11 from both sides, we get:

-2 x + 11 - 11 < 3 x + 5 - 11

or, - 2 x < 3 x-6

or, 6 < 5 x

or, x > 6/5

Hence, combining two solutions, we get: 6/5 < x < 10/3

So, the desired value of x should be more than (6/5) but less than (10/3)

6 0

3 years ago

What is the correctly result for 2+(3-4)*9

Greeley [361]

-7 is the correct result of that equation

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3 years ago

Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a

earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

Solution:

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

Alex is 12 years older than George

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

Carl is Three times older than Alex

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

The sum of their ages is 68

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

Substitute eqn 1 and eqn 2 in eqn 3

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

Substitute a = 16 in eqn 2

c = 3(16) = 48

c = 48

Substitute a = 16 in eqn 1

g = 16 - 12 = 4

g = 4

Find the ratio of George’s age to Carl’s age to Alex’s age

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

6 0

3 years ago

How to round to the nearest 10​

How to round to the nearest 10