Since E is the midpoint, DE and EF are the same length.
Set the equation DE and EF equal to each other and solve for x.
2x + 4 = 3x - 1
x = 5
Then plug in 5 to find the length.
DE = 2(5) + 4 = 14
EF = 3(5) - 1 = 14
DF = DE + EF = 28
Answer:
No
Step-by-step explanation:
For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.
I hope this helps! :)
5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
Answer:

Step-by-step explanation:
Co-ordinates of point A = ( -7 , 1 )
Co-ordinates of point M = ( -2 , 2 )
Let the co-ordinates of point B be ( x , y )
A ( -7 , 1 )
( x1 , y1 )
B ( x , y )
( x2 , y2 )
Now,
Midpoint = 
⇒
Finding the value of x :
⇒
Do cross multiplication
⇒
⇒
⇒
⇒
Now, finding the value of y
⇒
Do cross multiplication
⇒
⇒
⇒
⇒
Hence, The co-ordinates of point B = ( 3 , 3 )
Hope I helped!
Best regards!
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