You answer 82% of the questions correctly on a 50-question test. How many questions do you answer incorrectly
1 answer:
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Answer:
The correct option is;
Shirt Express charges less per shirt. For the cost to be the same 74 shirts must be ordered
Step-by-step explanation:
1) The given table for Shirt Express can be used to find the equation of the total cost of each made by Shirt Express as follows;
The rate of change of the function m is given as follows;
Therefore, we have;
m = (438 - 353)/(50 - 40) = 8.5
Te equation in slope and intercept form is then y - 438 = 8.5(x - 50)
From which we have;
y = 8.5·x - 8.5×50 + 438 = 8.5·x + 13
y = 8.5·x + 13
Therefore, Shirt Express initially charges 13 per shirt which is less than the 50 Shirt Custom charges
2) the cost to be the same, we equate both shirts equations to get;
8.5·x + 13 = 8·x + 50
0.5·x = 50 - 13 = 37
x = 37/0.5 = 74 shirts
Therefore, for the cost to be the same 78 shirts must be ordered
Answer:
We can conclude that her walking speed is 2.1 miles per hour.
Step-by-step explanation:
We have the relation:
Speed = distance/time.
Here we know:
She walked for 44 miles.
And she ran along the same route, so she ran for 44 miles.
The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:
T + T' = 22 hours.
If we define: S = speed runing
S' = speed walking
Then we know that:
"and she ran 33 miles per hour faster than she walked."
Then:
S = S' + 33mi/h
Then we have four equations:
S'*T' = 44 mi
S*T = 44 mi
S = S' + 33mi/h
T + T' = 22 h
We want to find the value of S', the speed walking.
To solve this we should start by isolating one of the variables in one of the equations.
We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:
S'*T' = 44mi
(S' + 33mi/H)*T = 44mi
T + T' = 22h
Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:
T = 22h - T'
if we replace that in the other equations we get:
S'*T' = 44mi
(S' + 33mi/h)*( 22h - T') = 44 mi
Now we can isolate T' in the first equation to get:
T' = 44mi/S'
And replace that in the other equation so we get:
(S' + 33mi/h)*( 22h -44mi/S' ) = 44 mi
Now we can solve this for S'
22h*S' + (33mi/h)*22h + S'*(-44mi/S') + 33mi/h*(-44mi/S') = 44mi
22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi
If we multiply both sides by S' we get:
22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'
We can simplify this to get:
22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0
22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0
This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:
Then the two solutions are:
S' = (-628mi - 721mi)/44h = -30.66 mi/h
But this is a negative speed, so this has no real meaning, and we can discard this solution.
The other solution is:
S' = (-628mi + 721mi)/44h = 2.1 mi/h
We can conclude that her walking speed is 2.1 miles per hour.