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seraphim [82]
3 years ago
12

-15=-4m+58n+7=31-10=10(k-9)

Mathematics
2 answers:
Korolek [52]3 years ago
6 0
-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}

=========================================================

8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}

=========================================================

10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}
Mashutka [201]3 years ago
6 0
1)\ \ \ -15=-4m+5\\-15-5=-4m\\-20=-4m\ /:(-4)\\5=m\\m=5\\\\2)\ \ \ 8n+7=31\\8n=31-7\\8n=24\ /:8\\n=3\\\\3)\ \ \ -10=10(k-9)\ /:10\\-1=k-9\\-1+9=k\\8=k\\k=8
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The sum of the first term of an ap is 240 and the sum of the next 4 term is 220 find the first term of the ap
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Answer:

The common difference is -5/4

T(n) = T(0)  - 5n/4,

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Assuming T(0) = 0, then first term

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Step-by-step explanation:

T(n) = T(0) + n*d

Let

S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240

S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220

S2 - S1

= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)

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= 4(4)d

= 16d

Since S2=220,  S1 = 240

220-240 = 16d

d = -20/16 = -5/4

Since T(0) has not been defined, it could be any number.

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