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makvit [3.9K]
3 years ago
7

What is the slope of this line? The coordinates are: (-4,5),(0,6), and (8,8).

Mathematics
2 answers:
ANTONII [103]3 years ago
5 0

Answer:

The slope of the line is 1/4.

Step-by-step explanation:

To find the slope of any line, use the slope formula.

m = (y2 - y1)/(x2 - x1)

m = (6 - 5)/(0 - -4)

m = (6 - 5)/(0 + 4)

m = 1/4

Elodia [21]3 years ago
4 0

Answer:


Step-by-step explanation:

we have to use the formula of slope here.

we know,

slope of the line passing through (x1,y1) and (x2,y2) is-

\frac{y2-y1}{x2-x1}

Here, the first two points are -

(-4 , 5) and (0,6)

So, the slope will be-

\frac{6-5}{0-(-4)}=\frac{1}{0+4}=\frac{1}{4}


So, the slope is-

\frac{1}{4}

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Answer:

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Step-by-step explanation:

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3 years ago
: Solve for the variable x3+7=20 s.
german

Answer:

x = (13) ^ 1/3

x is approximately 2.351334688

Step-by-step explanation:

x^3 + 7 = 20

Subtract 7 from each side

x^3 + 7-7 = 20-7

x^3 = 13

Take the cube root of each side

x^3 ^ 1/3  = (13) ^ 1/3

x = (13) ^ 1/3

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3 years ago
Read 2 more answers
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

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3 years ago
Very quick definition: What do you call the relation between two points that have one or more points in between them? For exampl
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Answer:

Step-by-step explanation:

Well believe it or not, that is not a simple question. Just look at what you left us to define. Your talking (for example) about a square and wondering what the vertex of B is called (other than a vertex.)

I think vertex is the only thing you can call B. But then there's a problem. What do you call the points on a segment? ___________? There are endpoints, but what's between those endpoints? I think you would just give them letter names and call them points. A point is dimensionless and there an infinite number of them in a segment.

Phew!!!

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Which linear inequality is represented by the graph?
Ksju [112]

Tthe inequality that describes this graph is y ≤ 1/3x - 4/3

<h3>How to determine the linear inequality represented by the graph?</h3>

The graph that completes the question is added as an attachment

From the attached graph, we have the following points

(0, -1.3) and (3, -0.3)

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (-0.3 + 1.3)/(3 - 0)

Evaluate

m = 1/3

The equation is then calculated as:

y = m(x - x1) + y1

This gives

y = 1/3(x - 0) - 1.3

Evaluate

y = 1/3x - 4/3

From the graph, we have the following highlights:

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The first highlight above implies, the inequality can be any of ≥ and ≤

While the second highlight above implies, the inequality is ≤

Hence, the inequality that describes this graph is y ≤ 1/3x - 4/3

Read more about inequality at

brainly.com/question/24372553

#SPJ1

3 0
1 year ago
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