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ira [324]
4 years ago
14

Solve the equation 4x^2-17x-15=0

Mathematics
2 answers:
Mnenie [13.5K]4 years ago
8 0
4x^2-17x-15=0\\
4x^2-20x+3x-15=0\\
4x(x-5)+3(x-5)=0\\
(4x+3)(x-5)=0\\
x=-\frac{3}{4} \vee x=5
nevsk [136]4 years ago
3 0
4x^2 - 17x - 15 = 0
(4x + 3)(x-5)
4x + 3 = 0
4x = -3
x = -3/4

x - 5 = 0
x = 5
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Step-by-step explanation:

Let the other be = x


As the sum of the number is given as \frac {7}{8}

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According to question


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Subtracting \frac{3}{4} from both sides we get


\frac{3}{4} +x - \frac{3}{4} = \frac{7}{8} - \frac{3}{4}


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And making

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Multiply \frac{3}{4} by 2 in numerator and denominator and multiply \frac {7}{8} by 1 in numerator and denominator we get


x= \frac{7}{8} - \frac{6}{8}


x= \frac{7-6}{8}


x =\frac{1}{8}


Hence, the other number is \frac{1}{8}


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