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Natasha2012 [34]
3 years ago
10

Suppose you purchase a car for $24,500, and it depreciates at the rate of $1500 a year. Express the car's value after five years

as a term in an arithmetic sequence.
Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Answer:

The arithmetic sequence is

24,500,23,000, 21,500,20,000,18,500,17,000

The car's value after five years is $17,000

Step-by-step explanation:

Let

n -----> the number of years

a(n) ----> the car's value

we know that

The arithmetic sequence that represent this situation is

a(n)=-1,500n+24,500

where

-1,500 is the common difference

so

For n=0 (initial value)

a(0)=-1,500(0)+24,500=24,500

For n=1 (First year)

a(1)=-1,500(1)+24,500=23,000

For n=2 (Second year)

a(2)=-1,500(2)+24,500=21.500

For n=3 (Third year)

a(3)=-1,500(3)+24,500=20,000

For n=4 (Fourth year)

a(4)=-1,500(4)+24,500=18,500

For n=5 (Fifth year)

a(5)=-1,500(5)+24,500=17,000

The arithmetic sequence is

24,500,23,000, 21,500,20,000,18,500,17,000

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