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tresset_1 [31]
3 years ago
10

13 units from (10,6)

Mathematics
1 answer:
svp [43]3 years ago
5 0
The answer is ( 23,7)
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What is the perimeter of this triangle?
salantis [7]

3w-15 is the answer ,

w + w + w-15

( combime like terms )

= 3w - 15


6 0
3 years ago
Please help me. Explain I don’t understand this
s2008m [1.1K]

Answer:

-9

Step-by-step explanation:

-6/2 + -6 =

-6 divided by 2 = -3 =

-3+-6=

-9

7 0
3 years ago
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What is the length of GH¯¯¯¯¯¯, to the nearest tenth of a meter? 7.3 m 13.7 m 14.1 m 19.4 m A scalene triangle G H J. The base s
nlexa [21]
By applying the law of sines.

\frac{GH}{sin \ J} =  \frac{GJ}{sin \ H}

Given:
<span>GJ = 10 , ∠J =45° , ∠H = 31°

∴ </span><span>\frac{GH}{sin \ 45} =  \frac{10}{sin \ 31}

∴ GH = 10 * sin 45° / sin 31° ≈ 13.7 m
</span>
8 0
3 years ago
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What is the best approximation of the projection of (5,-1) onto (2,6)?
Hatshy [7]

Answer:

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

Step-by-step explanation:

We have given two points  (5, -1) and (2, 6).

Let,     \vec a=5\hat {i}-\hat {j}  and  \vec b= 2\hat {i}+6\hat{j} .

and we have calculate the projection of \vec a onto \vec b.

Now,

For the calculation of projection, first we need to calculate the dot product of  \vec a  and \vec b.

\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})

     =10-6

     =4

then, we have to calculate the magnitude of \vec b.

   \mid {\vec {b}}\mid = \sqrt{2^{2}+6^{2}  } = \sqrt{40} = 2\sqrt{10}.

Now, the scalar projection of \vec a onto \vec b = \frac{\vec a.\vec b}{\mid b\mid}

                                                                 = \frac{4}{2\sqrt{10} }\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}

and the vector projection of \vec a onto \vec b = \frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b

                                                               = \frac{4}{40} . (2\hat i+ 6\hat j)

                                                                = \frac{1}{5} \hat i+\frac{3}{5} \hat j

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

                                                               

6 0
3 years ago
I need help please i’ll mark you brainliest
3241004551 [841]
3 = x - 5 is a possible answer
6 0
3 years ago
Read 2 more answers
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