<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
I can tell you the first one and you can figure it out from there. 70 is 40% persent of what number? Well, we can chop 40% to 20% and chop 70 in half and we get 35. So 35 = 20% So we multiply 35 by five, and get 175. So 70 is 40% of 175.
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
Rip
Christy c = 90 min
kids k = 120 min
total time t = ?
I would do : 90+120 = 210 then divide that by 2 which equals 105 min
Mae walked 8 3/10 km on the last day.
If you add 4 2/5+5+7 3/10=16 7/10. Then you subtract 16 7/10 from the total, or 25 km and get 8 3/10 km. Hope this helped:)
