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Oliga [24]
3 years ago
14

Sarah solves the equation as shown. 2(x + 3) = 8 1. 2x + 6 = 8 2. 2x = 2 3. x = 1 In which step did Sarah use the distributive p

roperty?
Mathematics
2 answers:
frez [133]3 years ago
7 0
3. X=1. Remember PEMDAS!
2(x+3)=8
2•x +2•3
2+6=8
marishachu [46]3 years ago
6 0

Answer:

Sarah use distributive property in Step 1.

Step-by-step explanation:

Consider the provided equation.

2(x + 3)=8

Step 1: Use the distributive property a(b+c)=ab+ac

2x + 6=8

Step 2: Subtract 6 from both sides.

2x + 6-6=8-6

2x =2

Divide 2 from both the sides.

x =1

Now we need to find in which step Sarah use distributive property.

From the above calculation we can be concluded that Sarah use distributive property in Step 1.

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Step-by-step explanation:

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Find the volume of the cone shown below.
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Answer:

D

Step-by-step explanation:

The formula for volume of cone is  V=\frac{1}{3}\pi r^2 h

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V is the volume

r is the radius of the circular base

h is the height of the cone

<em>In the diagram shown, we can clearly see that height is 12, radius is 9. We can simply plug them into the formula and get our exact answer (leaving pi as pi):</em>

<em>V=\frac{1}{3}\pi (9)^2(12)\\=324 \pi</em>

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What is the factor of 3x2-9x-12?<br> pleaseeee help me guys !!
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Answer:3x² - 9x - 12 =

3(x² - 3x - 4) =

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Step-by-step explanation:

8 0
3 years ago
The distribution of lifetimes of a particular brand of car tires has a mean of 51,200 miles and a standard deviation of 8,200 mi
Orlov [11]

Answer:

a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 51200, \sigma = 8200

Probabilities:

A) Between 55,000 and 65,000 miles

This is the pvalue of Z when X = 65000 subtracted by the pvalue of Z when X = 55000. So

X = 65000

Z = \frac{X - \mu}{\sigma}

Z = \frac{65000 - 51200}{8200}

Z = 1.68

Z = 1.68 has a pvalue of 0.954

X = 55000

Z = \frac{X - \mu}{\sigma}

Z = \frac{55000 - 51200}{8200}

Z = 0.46

Z = 0.46 has a pvalue of 0.677

0.954 - 0.677 = 0.277

0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

B) Less than 48,000 miles

This is the pvalue of Z when X = 48000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{48000 - 51200}{8200}

Z = -0.39

Z = -0.39 has a pvalue of 0.348

0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

C) At least 41,000 miles

This is 1 subtracted by the pvalue of Z when X = 41,000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{41000 - 51200}{8200}

Z = -1.24

Z = -1.24 has a pvalue of 0.108

1 - 0.108 = 0.892

0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

D) A lifetime that is within 10,000 miles of the mean

This is the pvalue of Z when X = 51200 + 10000 = 61200 subtracted by the pvalue of Z when X = 51200 - 10000 = 412000. So

X = 61200

Z = \frac{X - \mu}{\sigma}

Z = \frac{61200 - 51200}{8200}

Z = 1.22

Z = 1.22 has a pvalue of 0.889

X = 41200

Z = \frac{X - \mu}{\sigma}

Z = \frac{41200 - 51200}{8200}

Z = -1.22

Z = -1.22 has a pvalue of 0.111

0.889 - 0.111 = 0.778

0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

4 0
3 years ago
Together, teammates Pedro and Ricky got 2682 base hits last season. Pedro had 282 more hits than Riley. How many hits did each p
pickupchik [31]

Pedro had 1482 hits and Riley had 1200 hits.

Step-by-step explanation:

Given,

Number of base hits = 2682

Let,

Number of Pedro's hits = x

Number of Riley's hits = y

According to given statement;

x+y=2682    Eqn 1

x = y+282    Eqn 2

Putting value of x from Eqn 2 in Eqn 1

(y+282)+y=2682\\y+282+y=2682\\2y=2682-282\\2y=2400

Dividing both sides by 2

\frac{2y}{2}=\frac{2400}{2}\\y=1200

Putting y=1200 in Eqn 2

x=1200+282\\x=1482

Pedro had 1482 hits and Riley had 1200 hits.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/9532142
  • brainly.com/question/9381080

#LearnwithBrainly

4 0
3 years ago
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