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2 years ago

Factoring trinomials????x^2+8x+15

Mathematics

2 answers:

DiKsa [7]2 years ago

6 0

X^2+8x+15

= x^2 + 5x + 3x + 15

= x(x+5) + 3(x+5)

= (x+5)(x+3)

Scilla [17]2 years ago

4 0

You nee 2 numbers whose sum is +8 and whose product is +15.

That is 3 and 5.

so the answer is (x + 3)(x + 5)

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What is the largest power of 2 that is a divisor of 13^4 - 11^4?

OverLord2011 [107]

Answer:

$2^5$

Step-by-step explanation:

Given:

$(13^4 - 11^4)(13^2+11^2)$

add all together with exponents

=48*290

= Then turn into a smaller exponent

= $2^4 * 3 * 2*145$

combine like terms

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2 years ago

Read 2 more answers

A piece of green jade has a mass of 23.401 g.if the sample of jade displaces 50.0 ml of water to 56.5 ml in a 100 ml graduated c

OleMash [197]

we know that

The density is equal to the formula

$Density=\frac{mass}{volume}$

in this problem we have

$mass=23.401\ gr$

<u>Find the volume of a piece of green jade</u>

$Volume=56.5\ ml-50.0\ ml=6.5\ ml$

Substitute the values in the formula of density

$Density=\frac{23.401}{6.5}$

$Density=3.60\frac{gr}{ml}$

therefore

<u>the answer is</u>

$Density=3.60\frac{gr}{ml}$

3 0

3 years ago

3(x-2)5 simplified and tiles

BartSMP [9]

Answer:

Step-by-step explanation:

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2 years ago

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment. Find the margin of error for the 95% confiden

Vlad [161]

Answer:

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.

This means that $n = 2161, \pi = \frac{1214}{2161} = 0.5618$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{0.5618*0.4382}{2161}}$

$M = 0.0209$

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

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Answer:

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Step-by-step explanation:

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