You could just use a calculator. Or, simply find the largest perfect square that is a factor of the number and then put the multiplier under a radical sign.
Answer: The length of JF = 16 units.
Step-by-step explanation:
Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.
i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]
If EJ is 3y-8 and JF is 7y-40.
Then, 
![\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%207y-3y%3D40-8%5C%5C%5C%5C%5CRightarrow%5C%204y%3D32%5C%5C%5C%5C%5CRightarrow%5C%20y%3D8%20%5Ctext%7B%20%5BDivide%20both%20sides%20by%204%5D%7D)
JF= 7(8)-40 =56-40= 16 units
Hence, the length of JF = 16 units.
Answer:
m∠3 = 112° m∠5 = 38° m∠6 = 68° m∠8 = 74°
You do the others
Step-by-step explanation:
Facts you need to solve this problem.
1. Vertical angles are congruent
2. Alternate interior angles are congruent when lines are parallel
3. Sum of the measures of the angles of a triangle is 180
4. Adjacent angles are supplementary when two lines intersect
m∠3 = 112° (Reason 1 above)
m∠6 = 180 - 112 = 68° (Reason 4)
m∠6 + m∠5 + 74 = 180° (Reason 3)
68 + m∠5 + 74 = 180
142 + m∠5 = 180
m∠5 = 38°
m∠8 = 74° (Reason 2)
That gives you a start, so I will let you find all the others. OK? I know you don't want to do that, but you need to be able to do this type of problem. Now, go for it!!
Tan (10 degrees) = 1983 / distance
distance = 1983 / tan (10 degrees)
distance = 1983 / 0.17633
<span><span><span>distance = 11,246</span> feet
11,246 / 5,280 = 2.13 miles</span> </span>
Answer:
x=13
Step-by-step explanation: