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NikAS [45]
3 years ago
11

Find the missing value for the exponential function represented by the table below x -2 -1 0 1 2 y 29 20.3 14.21 6.9629

Mathematics
1 answer:
andre [41]3 years ago
5 0

Answer:

y=4.8710 is the missing value

Step-by-step explanation:

The first step in approaching this question is determining the exponential equation that models the set of data. This can easily be done in Ms.Excel application. We first enter the data into any two adjacent columns of an excel workbook. The next step is to highlight the data, click on the insert tab and select the x,y scatter-plot feature. This creates a  scatter-plot for the data.

The next step is to click the Add chart element feature and insert an exponential trend line to the scatter plot ensuring the display equation on chart is checked.

The exponential regression equation for the data set is given as;

y=12.321e^{-0.464x}

To find the missing y value, we simply substitute x with 2 in the regression equation obtained;

y=12.321e^{-0.464(2)}\\\\y=4.8710

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One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?
hram777 [196]
Consider this solution, if it is possible, check the result:
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elixir [45]

Answer:

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Step-by-step explanation:

We want to simplify:

( - 2 {x}^{4} {y}^{ - 3} )^{4}

We need to apply the exponential property for products of powers.

Recall that:

( {a}^{m}  \times  {a}^{n} )^{p}  =  {a}^{mp}  \times  {a}^{np}

We apply this rule to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = ( { - 2)}^{4} x \times {x}^{16}  \times {y}^{ - 12}

This simplifies to:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = 16 {x}^{16}  \times {y}^{ - 12}

We rewrite as positive index to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  =  \frac{16 {x}^{16}}{ {y}^{12} }

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Read 2 more answers
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ruslelena [56]
The numbers are:  "7 " and "21 " .
_______________________________________
Explanation:
_______________________________________
The numbers are:  "x"  and "x + 14" .

x + (x + 14) = 28 .  Solve for "x" ; and then solve for "x + 14" .
_______________________________________
 → x + (x + 14) = 28 ;

Rewrite as:

 →  x + x + 14 = 28 ;

 →  1x + 1x + 14 = 28 ;

 →  2x + 14 = 28 ; 
  
 Subtract "14" from each side of the equation;
 
 →  2x + 14 − 14 = 28 <span>− 14 ;

</span> →  2x = 14  ;

Divide EACH SIDE of the equation by "2" ;
     to isolate "x" on one side of the equation; & to solve for "x" ;

 →  2x / 2 = 14 / 2 ;

 →  x = 7 . 
_________________________________________
So;  one of the numbers is:  " 7 " .

The other number is:  " x + 14 " ; which equals: " 7 + 14 = 21".

The other number is:  "21 " .
_________________________________________
The numbers are:  "7 " and "21 " .
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