Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
Explanation:
a)


b) First, we have that

On the other hand,

Therefore, both expressions are equal. This makes sense, because selecting k elements from a group of n is the same than specify which elements you will not select. In order to specify those elements you need to select the n-k elements that will not be selected. Hence, each time you are selecting k from n, you are also selecting n-k from n, and from that reason both combinatorial numbers are equal.
Answer:
20
Step-by-step explanation:
add all the numbers then divide by how many numbers there are.
Answer:
happy birth day
Step-by-step explanation:
Answer:
x=31
y=15
Step-by-step explanation:
let x and y be the 2 part
x+y=46
x-2y=1 ⇒ x=1+2y
substitute :
1+2y+y=46
3y=46-1
3y=45 ⇒ y=45/3=15
x-2y=1
x-2(15)=1 ⇒ x=1+30 ⇒x=31
x= 2 times y(15)+1
y=15
31+15=46