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Harlamova29_29 [7]
3 years ago
15

Which is the solution set for –7 ≤ 4x + 1 ≤ 5? I added a picture !

Mathematics
2 answers:
Bess [88]3 years ago
8 0
-7\leq4x+1\leq5\\
-8\leq4x \leq4\\
-2\leq x\leq1 \Longleftrightarrow x\geq-2 \wedge x\leq1 \Rightarrow C

Oksi-84 [34.3K]3 years ago
6 0
-7\leq4x+1\leq5\ \ \ \ |subtract\ 1\\\\-7-1\leq4x+1-1\leq5-1\\\\-8\leq4x\leq4\ \ \ \ |divide\ by\ 4\\\\-8:4\leq4x:4\leq4:4\\\\\boxed{-2\leq x \leq1\Rightarrow x\in[-2;\ 1]}

\boxed{x\geq-2\ and\ x\leq1}\to\answer{\boxed{C}}
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3 years ago
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timofeeve [1]

Answer:

x = -70

Step-by-step explanation:

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7 0
4 years ago
Suppose <br> f '(x) = xe^−x^2
iogann1982 [59]
<h3>Answers:</h3>
  • (a) The function is increasing on the interval (0, infinity)
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Explanation:

You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).

The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)

Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)

6 0
3 years ago
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Contact [7]
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Hope this helps if so please mark me as brainlest thank you !!
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3 years ago
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Answer:

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Step-by-step explanation:

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