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2 years ago

Omar, Amare, and Jack paid a total of $68.25 for dinner and tickets to a concert. The concert

Mathematics

2 answers:

Andrews [41]2 years ago

8 0

Answer: I’m having problems to

Step-by-step explanation:

Marina86 [1]2 years ago

4 0

Answer: $13

Step-by-step explanation:

To determine the solution arithmetically in two steps, first divide 68.25 by 3 and then subtract 9.75 from the result. To determine the solution algebraically, set up and solve the equation 3(x+9.75)=68.25. Each friend paid $13 for dinner.

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Help please ASAP thank you

jonny [76]

<u>Question 1</u>

If we let $FE=x$ , then $DE=x-5$ .

Also, as $\overline{DF}$ bisects $\overline{BC}$ , this means $BE=EC=6$ .

Thus, by the intersecting chords theorem,

$6(6)=x(x-5)\\\\36=x^2 - 5x\\\\x^2 - 5x-36=0\\\\(x-9)(x+4)=0\\\\x=-4, 9$

However, as distance must be positive, we only consider the positive case, meaning FE=9

<u>Question 2</u>

If we let CE=x, then because AB bisects CD, CE=ED=x.

We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.

By the intersecting chords theorem,

$2(32)=x^2\\\\64=x^2\\\\x=-8, 8$

However, as distance must be positive, we only consider the positive case, meaning CE=8

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1 year ago

Write 22 decreased by 6 as an algebraic expression

Alona [7]

Answer:

22-6

Step-by-step explanation:

there isnt a variable so the answer is 16

6 0

2 years ago

Read 2 more answers

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

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3 years ago

Can anyone help me with this dont answer if you dont no what it is and no deleting answers

Mkey [24]

The answer to this question is the second choice, jessica bought 1/4 more than derek

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1 year ago

I NEED HELP FAST!

Degger [83]

Answer:

Step-by-step explanation:

4.5×5.5=24.75

so 24.75 is the area of the room but you have to buy whole tiles so you would need to but 25 tiles

8 0

2 years ago