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gizmo_the_mogwai [7]

4 years ago

9

Explain the systematic trial method for solving equations

1 answer:

adoni [48]4 years ago

8 0

Systematic sampling is a type of probability sampling method in which sample members from a larger population are selected according to a random starting point but with a fixed, periodic interval. This interval, called the sampling interval, is calculated by dividing the population size by the desired sample size.

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PLEASE HELP PICTURE IS SHOWN

IrinaVladis [17]

I have attached the graph so you can compare but it is graph C.

Hope that helps.

6 0

3 years ago

Can somebody help me out? This is due so soon

olga_2 [115]

Answer:

y = $\frac{1}{2}$ x + $\frac{3}{20}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 10x - 20y = - 3 into this form

Subtract 10x from both sides

- 20y = - 10x - 3 ( divide all terms by - 20 )

y = $\frac{-10}{-20}$ x - $\frac{3}{-20}$ , that is

y = $\frac{1}{2}$ x + $\frac{3}{20}$ ← in slope- intercept form

6 0

4 years ago

Select the correct answer. Which expression is equivalent to this polynomial? 16x² +4

lana66690 [7]

Answer:

(4x+2)(4x-2)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Compute log337 in terms of common or natural logs..<br>

Gre4nikov [31]

Answer:

log 337

Using log a x = ln x /ln a

Change the base of the logarithm

For log 337

We get

ln 337 / ln 10

= 2.52763

Hope this helps.

6 0

3 years ago

Which of the following is a root of the polynomial shown below?

Mademuasel [1]

Answer:

We conclude that option A is true as x = 1 is the root of the polynomial.

Step-by-step explanation:

Given the polynomial

$f\left(x\right)\:=\:x^2\:+\:2x^2\:-\:x-2$

Let us determine the root of the polynomial shown below.

$\:0=\:x^2\:+\:2x^2\:-\:x-2$

$0=3x^2-x-2$

switch sides

$3x^2-x-2=0$

as

$3x^2-x-2=\left(3x+2\right)\left(x-1\right)$

so the equation becomes

$\left(3x+2\right)\left(x-1\right)=0$

Using the zero factor principle

$3x+2=0\quad \mathrm{or}\quad \:x-1=0$

solving

$3x+2=0$

$3x=-2$

$\frac{3x}{3}=\frac{-2}{3}$

$x=-\frac{2}{3}$

and

$x-1=0$

$x=1$

The possible roots of the polynomial will be:

$x=-\frac{2}{3},\:x=1$

Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.

3 0

3 years ago