Answer:
The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.
The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

Given:

*Use the <em>t</em>-table for the critical value.
Compute the 99% confidence interval as follows:

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).
I dont know if i did this right but here
x1 = 9.5 y1 = 0
If you would like to solve for the variable in the proportion 6/34 = D/68, you can do this using the following steps:
6/34 = D/68<span> /*68
</span>D = 6/34 * 68
D = 12
The correct result would be <span>D = 12</span>.
Your answer is going to be -2.7, -0.6, -0.5
To figure out which numbers are greater than others, you just need to look at a number line. There are two sides to a number line, with 0 being in the middle. When looking to the negative (left) side, the further left you go, the smaller the numbers will be. However, when looking to the positive (right) side of the 0, the numbers gradually get bigger.
Do you have any answer choices?