i can only help you with the volume of #5.
So the volume of a cylinder is = πr²h.
First , put the numbers in the equation.
π(6)² (14)
Next you solve.
π(6)²(14) = 36 (14) π = 504π
V= 504π
Answer:
B: -6+2i
Step-by-step explanation:
- 3i + (-6 - i) = ⇒ open parenthesis
- 3i - 6 - i = ⇒ simplify
- -6 + 2i ⇒ answer in standard form of a+bi
Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
