All categories

3 years ago

A statement and portions of the flowchart proof are shown. Which reason should appear in box labeled 1?

Mathematics

1 answer:

larisa [96]3 years ago

4 0

Answer:

Angle Addition Postulate

Step-by-step explanation:

Given:

$m\angle UVW=30^{\circ}\\ \\m\angle WVX=75^{\circ}$

Prove:

$m\angle UVX=105^{\circ}$

Proof:

1. $m\angle UVX=m\angle UVW+m\angle WVX$ - Angle Addition Postulate

2. $m\angle UVW=30^{\circ}$ - given

3. $m\angle WVX=75^{\circ}$ - given

4. $m\angle UVX=30^{\circ}+75^{\circ}$ - Substitution Property of Equality

5. $m\angle UVX=105^{\circ}$ - Simplify

You might be interested in

Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050

weeeeeb [17]

(12,200 + 16,211 + 12,050 + 11,350 + 13,325) / 5 = 65136/5 =
13027.2 <== this is the mean (average)

11,350 , 12,050 , 12,200 , 13,325, 16,211
median (middle number) = 12,200

there is no mode...a mode is a number that appears most often...all the numbers appear once in this data.

4 0

3 years ago

Read 2 more answers

Define right triangle.

Firdavs [7]

Answer:

A right triangle is a triangle that has one 90 degree angle, so looking at the options i would say D

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Determine whether the function f(x)= 1/x^2 is even, odd or neither.

gulaghasi [49]

The function f(x)= 1/x^2 is even. Hope that helps!

4 0

3 years ago

PLEASE HELP QUICK

son4ous [18]

A should be the correct answer

7 0

3 years ago

Read 2 more answers

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago