Explanation: We can set the variable for the first integer of the three consecutive integers as x.
First integer=x
Because they are all odd, we can then say that the second integer is equal to the first integer plus 2.
Second integer=x+2
Using the same knowledge, we can say that the third integer is equal to the second integer plus 2.
Third integer=x+2+2 Third integer=x+4.
Now, we have our three integers: First integer=x Second integer=x+2 Third integer=x+4
We can write out equation out like this: (x)+(x+4)=(x+2)+33 The sum of the first (x) and third (x+4) integers is equal to the sum of the second (x+2) and 33.
Now, we solve this equation. (x)+(x+4)=(x+2)+33 Open up the parentheses x+x+4=x+2+33 Combine like terms 2x+4=x+35 Subtract both sides by 4 2x+4-4=x+35-4 2x=x+31 Subtract both sides by x 2x-x=x+31-x x=31
Now, we know that our first integer is 31. Because these integers are consecutive and odd, we know that our second integer is 33 and the third is 35.
