Explanation: We can set the variable for the first integer of the three consecutive integers as x.
First integer=x
Because they are all odd, we can then say that the second integer is equal to the first integer plus 2.
Second integer=x+2
Using the same knowledge, we can say that the third integer is equal to the second integer plus 2.
Third integer=x+2+2 Third integer=x+4.
Now, we have our three integers: First integer=x Second integer=x+2 Third integer=x+4
We can write out equation out like this: (x)+(x+4)=(x+2)+33 The sum of the first (x) and third (x+4) integers is equal to the sum of the second (x+2) and 33.
Now, we solve this equation. (x)+(x+4)=(x+2)+33 Open up the parentheses x+x+4=x+2+33 Combine like terms 2x+4=x+35 Subtract both sides by 4 2x+4-4=x+35-4 2x=x+31 Subtract both sides by x 2x-x=x+31-x x=31
Now, we know that our first integer is 31. Because these integers are consecutive and odd, we know that our second integer is 33 and the third is 35.
Its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.
