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grin007 [14]
2 years ago
9

The numbers 5 and -5 are opposites.explain why 5 and -5 have the same absolute value

Mathematics
1 answer:
Citrus2011 [14]2 years ago
3 0

Answer:

I think because the absolute value is always a positive number.

Step-by-step explanation:

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Can someone please help me with number 6?
Vlad1618 [11]

Step-by-step explanation:

substitute a with 2 and b with 3

2x+3

because it's the same equation it should just be an equal sign.

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Please help!!!!!!<br><br> Rewrite this equation in terms of y<br> 2x-3y=22
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The answer is y = 2/3x - 22/3
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Two lines, A and B, are represented by the equations given below: Line A: y = x − 6 Line B: y = 3x + 4 Which of the following sh
nadezda [96]

The solution to the system of linear equations is: (−5, −11).

<h3>What is the Solution to the System of Linear Equations?</h3>

The solution to a system is the x and y -coordinates that satisfies the two linear equations.

Given the linear equations:

Line A: y = x − 6

Line B: y = 3x + 4

Now, equating these two equations

x - 6 = 3x + 4

2x = -10

x = -5

y = -11

Hence, the solution is: (−5, −11), because the point satisfies both equations.

Learn more about solution to a system here:

brainly.com/question/13729904

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8 0
2 years ago
A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a
tatuchka [14]

Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

n=15 sample size  

\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

The statistic for this case would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

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3 years ago
Please help [photo attachment]
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Absolute Zero, also I suggest cropping out your name and teacher for your safety :3 have an amazing day!
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