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grin007 [14]
2 years ago
9

The numbers 5 and -5 are opposites.explain why 5 and -5 have the same absolute value

Mathematics
1 answer:
Citrus2011 [14]2 years ago
3 0

Answer:

I think because the absolute value is always a positive number.

Step-by-step explanation:

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4 times x with an exponent of 2 plus 2 times y with an exponent of 4. X=-3 y=2
Digiron [165]

Answer:

Step-by-step explanation:

Your equation is: 4*x^{2} +2 * y^{4}

You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

4*(-3)^{2} +2 * 2^{4}

First, you want to do the exponentiation (meaning you want to calculate (-3)^{2} and 2^{4} parts). (-3)^{2} equals 9 and 2^{4} equals 16.

So the equation now is:

4*9+2*16

Now you want to do multiplication. 4*9 equals 36 and 2*16 equals 32. So you're left with:

36+32

Which equals 68.

8 0
3 years ago
How do you show the mathematical equation for one lap around the track is 1/4 mile. jose wants to run 5 miles. how many times mu
Sindrei [870]
1/4=0.25 miles
5/0.25=20 laps
José has to run 20 laps to run 5 miles.
8 0
3 years ago
HELP ME PLEASE REALLY IMPORTANT OR ILL GET IN TROUBLE!! WILL MARK AS BRAINLEST IF YOU GET IT CORRECT!!
dmitriy555 [2]

Answer:

2n + 11

Step-by-step explanation:

You can combine 4n and -2n.

You get 2n + 11

8 0
3 years ago
A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p
gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0
3 years ago
This a 2 part question. F(x) is the graph shown.
Vlada [557]
Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].

Suppose f(x) is an odd function. What is the range of 0.5f(x-3) is [-1.5, 0.5]

5 0
3 years ago
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