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zzz [600]
2 years ago
11

What are these as equalivalent equations

Mathematics
1 answer:
tatiyna2 years ago
4 0

Answer:

6x - 2(x - 3) and x + 3(x - 2) - 6

The two expresaions that are quivalent are <u>6x - 2(x - 3)</u> and <u>x + 3(x - 2) - 6</u>.

Step-by-step explanation:

First expression which is 4(x - 3) is an example of a binomial that when multiplied together, the product would be 4x - 12. Therefore, second and third expressions are the answer.

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1-What is the sum of the series? ​∑j=152j​ Enter your answer in the box.
tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

1)

∑\left \ {{5} \atop {j=1}} \right. 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

  =  2 + 4 + 6 + 8 + 10

∑ = 30

2)

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑\left \ {{4} \atop {k=1}} \right. 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

  = 2(1) + 2(4) + 2(9) + 2(16)

  =  2 + 8 + 18 + 32

∑ = 60

∑\left \ {{4} \atop {k=1}} \right. (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

  = (2)² + (4)² + (6)² + (8)²

  = 4 + 16 + 36 + 64

∑ = 120

∑\left \ {{4} \atop {k=1}} \right. (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

  = (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

  = (4-4) + (16-4) + (36-4) + (64-4)

  = 0 + 12 + 32 + 60

∑ = 104

∑\left \ {{4} \atop {k=1}} \right. 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

  = 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

  = (2-4) + (8-4) + (18-4) + (32-4)

  = -2 + 4 + 14 + 28

∑ = 44

3)

∑\left \ {{6} \atop {k=3}} \right. (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)  

  = (6-10) + (8-10) + (10-10) + (12-10)

  = -4 + -2 + 0 + 2  

∑ = -4

4)

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1  = 1/2

1/16/1/8 = 1/16 * 8/1  = 1/2

1/32/1/16 = 1/32 * 16/1  = 1/2

1/64/1/32 = 1/64 * 32/1  = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

ar^{n-1} = 1(\frac{1}{2})^{n-1}

So the answer that represents the series in sigma notation is:

∑\left \ {{7} \atop {j=1}} \right. (\frac{1}{2})^{j-1}

5)

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So  

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑\left \ {{5} \atop {j=1}} \right. (2j−5)

6 0
3 years ago
Please answer quick and fast its due today.I only have two questions ​
madreJ [45]
#13 is 3000 because since each T-shirt is $650 and they buy 4 you multiply and get $2600 and since she received 400 dollar change then you add that value to the total cost and get 3000 that means she paid 3000

#14 is a millennium
1 year is 365 days
1 decade is 10 years
1 century is 100 years
1 millennium is 1000 years
So it has to be 1 millennium since 1000 years is the most out of the others
6 0
2 years ago
Read 2 more answers
Which term describes the slope of the line below?
saul85 [17]

Answer:

negative

Step-by-step explanation:

looking at the slope of the straight line, a positive slope will begin on the 1st quadrant and end at the 3rd quadrant

meaning if the slope is negative, it will begin on the 2nd quadrant and end on the 4th quadrant

5 0
2 years ago
Read 2 more answers
Find the diameter of the circle with the given circumference use 3.14 C=18
algol [13]
The formula for the circumference of a circle is pi * r * 2

First we solve for r (the radius)
pi*r*2 = C
pi*r*2 = 18

Divide 18 by 2
pi*r = 9

Then divide 9 by 3.14
pi= 9/3.14 which is 2.866

The diameter is 2 times length of the radius so multiply 2.866 by 2
The diameter is about 5.732
(And you can round of course)

Hope that helped
3 0
3 years ago
Value of x-y^x-y when x=2 and y=-2?​
Nonamiya [84]

Step-by-step explanation:

x-y^x-y

2-(-2)^2-(-2)

2-(-2)^2+2

2-(-2)^4

2-(16)

=-14

3 0
2 years ago
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