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Dmitrij [34]
2 years ago
11

It is estimated that world reserves of oil currently stand at 2625

Mathematics
1 answer:
seraphim [82]2 years ago
4 0

Answer:

  35.4 years

Step-by-step explanation:

The annual consumption (in billions of units) is described by the exponential function ...

  f(t) = 45.5·1.026^t

The accumulated consumption is described by the integral ...

  \displaystyle\int_0^t{f(x)}\,dx=45.5\int_0^t{1.026^x}\,dx=45.5\left(\dfrac{1.026^t-1}{\ln{1.026}}\right)

We want to find t such that the value of this integral is 2625, the estimated oil reserves.

  2625 = 45.5/ln(1.026)·(1.026^t -1)

  2625·ln(1.026)/45.5 +1 = 1.026^t ≈ 1.480832 +1 = 1.026^t

Taking natural logs, we have ...

  ln(2.480832) = t·ln(1.026)

  t ≈ ln(2.480832)/ln(1.026) ≈ 35.398

After about 35.4 years, the oil reserves will run out.

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Answer:

12.5cm

Step-by-step explanation:

This triangle is either isosceles or equilateral, we already know two sides.

the other side of the triangle is also 5 cm long because it is also the radius of the shape

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5 x 5 = 25

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Given that Ax - 4x² + 3x² + 4 = (x² - 2x + 1)(2x² + B) + C(x-1) + D for all values of x, evaluate A, B, C and D. Hence, deduce t
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5 0
2 years ago
Perform the multiplication, (7x2+a2)(x2–3a2)
aksik [14]

Answer:

The given multiplied expression is

(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

Step-by-step explanation:

Given expression is (7x^2+a^2)(x^2-3a^2)

To find the multiplication of the given expression :

(7x^2+a^2)(x^2-3a^2)

By using the distributive property to solve the given expression as below

(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)

=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2

=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}  ( by using the property a^m.a^n=a^{m+n} )

=7x^4-21x^2a^2+a^2x^2-3a^4

Adding the like terms in the above expression we get

=7x^4-20x^2a^2-3a^4

Therefore (7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

Therefore the given multiplied expression is

(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

8 0
3 years ago
A certain forest covers an area of 4300 km2 . suppose that each year this area decreases by 3.25% . what will the area be after
Gemiola [76]
A =P(1-3.25%)⁸

A= 3,301.23 km²
7 0
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