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k0ka [10]
3 years ago
13

Based on the company's collection history, 2% of credit sales are uncollectible, 40% are collected in month of sale and the rema

inder is collected in the following month. Total budgeted cash receipts in February 2014 are expected to be:
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

Therefore, option C is correct

Step-by-step explanation:

Budgeted cash receipts for February = 60000 + 303800*0.40 + 274400*.60

= 60000 +121520 + 164640

= 346160

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Which function has the same domain as y= 2√x?<br> Oy= √2x<br> O y=2³√x<br> 0₁y = √x-2<br> O y=³√x-2
dybincka [34]

The option first is correct because  y= 2√x and y= √2x have same domain which is x ≥ 0.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

y= 2√x

From the above function the domain should be:

x ≥ 0 (because square root of negative values does not exist)

The function:

y = √(2x)

2x ≥ 0

x ≥ 0

Thus, the option first is correct because  y= 2√x and y= √2x have same domain which is x ≥ 0.

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2 years ago
. Suppose a computer virus begins by infecting 8 computers in the first hour after it is released. Each hour after that, each ne
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3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
salantis [7]

Answer:

With​ 90% confidence, it can be said that the population mean price lies in the first interval. With​ 95% confidence, it can be said that the population mean price lies in the second interval. The​ 95% confidence interval is wider than the​ 90%.

Step-by-step explanation:

We are given that a random sample of 60 home theater systems has a mean price of​$131.00. Assume the population standard deviation is​$18.80.

  • Firstly, the pivotal quantity for 90% confidence interval for the  population mean is given by;

                            P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean price = $131

            \sigma = population standard deviation = $18.80

            n = sample of home theater = 60

            \mu = population mean

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics as we know about the population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                   of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                                  = [131-1.645 \times {\frac{18.8}{\sqrt{60} } } , 131+1.645 \times {\frac{18.8}{\sqrt{60} } } ]

                                                  = [127.01 , 134.99]

Therefore, 90% confidence interval for the population mean is [127.01 , 134.99].

  • Now, the pivotal quantity for 95% confidence interval for the  population mean is given by;

                            P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean price = $131

            \sigma = population standard deviation = $18.80

            n = sample of home theater = 60

            \mu = population mean

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about the population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                                  = [131-1.96 \times {\frac{18.8}{\sqrt{60} } } , 131+1.96 \times {\frac{18.8}{\sqrt{60} } } ]

                                                  = [126.24 , 135.76]

Therefore, 95% confidence interval for the population mean is [126.24 , 135.76].

Now, with​ 90% confidence, it can be said that the population mean price lies in the first interval. With​ 95% confidence, it can be said that the population mean price lies in the second interval. The ​95% confidence interval is wider than the​ 90%.

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Answer:

Step-by-step explanation:

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Answer:

4f=45\\\\Amount\ of\ fishes\ in\ each\ bucket=11.25\ pounds

Step-by-step explanation:

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