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Aleks [24]
3 years ago
9

The expected (mean) life of a particular type of light bulb is 1000 hours with a standard deviation of 50 hours. The life of thi

s world is normally distributed what is the probability that a randomly selected bulb would last fewer than 940 hours?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

11.5%

Step-by-step explanation:

To solve this problem, we can use the knowledge that there are z score tables that calculate probabilities based on z scores. Thus, we must calculate the z score.

The z score formula is \frac{x- m}{s} , where x is the value, m is the mean, and s is the standard deviation. We can then plug our values in to get \frac{940-1000}{50}  =  \frac{-60}{50} = -1.2 as our z score. Plugging this into a table where table values represent the area to the left of the z score (as we want to calculate everything under 940), we get 0.115, or 11.5% as our answer

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~~

I hope that helps you out!!

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