I need help plzzzz!!

The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a par

Kazeer [188]

#A

∆BCG and ∆BPE

#B

<B is common angle

Then

GPRC is parallelogram

<C+<CRP=180
<CRP+<BPE=180

From these

<C=<BPE

Hence from AA congruence the triangles are similar

#C

BE/BG=BC/BP
x/400=300/200
200x=120000
x=600ft

BE=600ft

And

CG/BG=PE/BE
350/300=PE/600
350=PE/2
PE=700ft

3 0

2 years ago

One number is 4 less than 3 times a second number. If 3 more than two times the first

Lelechka [254]

Answer:

The first number (x) = 8

Step-by-step explanation:

Let x = the first number

Let y = the second number

x = 3*y - 4

2x + 3 - 2y = 11 Subtract 3 from both sides

2x - 2y = 11 - 3

2x - 2y = 8 Divide by 2

x - y = 4 Add y to both sides

x = y + 4 Now go back to the very first equation. Substitute for x

y + 4 = 3y - 4 Subtract y from both sides

4 = 3y - y - 4

4 = 2y - 4 Add 4 to both sides

4 + 4 = 2y

8 = 2y Divide by 2

8/2 = y

y = 4

x = 3y - 4

x = 3*4 - 4

x = 12 - 4

x = 8

7 0

3 years ago

What is the rate on an investment that doubles $5051 in 9 years? Assume interest is compounded quarterly.

Inessa [10]

Answer:

The rate at which the investment gets double is 7.776

Step-by-step explanation:

Given as :

The principal investment = $ 5051

The time period of investment = 9 years

Let The rate of interest = R % compounded quarterly

The Amount gets double

So, <u>From Compounded method</u>

Amount = Principal × $(1+\dfrac{rate}{4\times 100})^{4\times Time}$

Or, 2 × P = P × ( 1 + $\dfrac{\textrm R}{400})^{\textrm 36}$

Or, 2 = ( 1 + $\dfrac{\textrm R}{400})^{\textrm 36}$

Or, $2^{\frac{1}{36}}$ = 1 + $\dfrac{\textrm R}{400}$

or, 1.01944 - 1 = $\dfrac{\textrm R}{400}$

or, 0.01944 = $\dfrac{\textrm R}{400}$

∴ R = 0.01944 × 400 = 7.776

Hence The rate at which the investment gets double is 7.776 Answer

7 0

3 years ago

What are your opinons on doge coin?

PolarNik [594]

Answer:

its dum ig

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.

vampirchik [111]

Answer:

The angle between the given vectors u and v is $\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Step-by-step explanation:

Given vectors are $\overrightarrow{u}=(3,4)$ and $\overrightarrow{v}=(1,3)$

Now compute the dot product of u and v:

$\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)$

$=(3)(1)+(4)(3)$

$=3+12$

$=15$

Now find the magnitude of u and v:

$|\overrightarrow{u}|=\sqrt{3^2+4^2}$

$=\sqrt{9+16}$

$=\sqrt{25}$

$=5$

$|\overrightarrow{u}|=5$

$|\overrightarrow{v}|=\sqrt{1^2+3^2}$

$=\sqrt{1+9}$

$=\sqrt{10}$

$|\overrightarrow{v}|=\sqrt{10}$

To find the angle between the given vectors

$\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta$

$\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Therefore the angle between the vectors u and v is

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

3 0

3 years ago