Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer: x = 15
9514 1404 393
Answer:
17/99
Step-by-step explanation:
Replace the digits 23 in your example with the digits 17 and you have your answer:
_____
In general, a 2-digit repeat will have 99 as its denominator. If the digits are a multiple of 3 or 11, then the fraction can be reduced. 17 is prime, so the fraction cannot be reduced.
Answer:
Step-by-step explanation:
8x+10 - 4x+16 = 4x-6
w= 2x-3
We have that
−27x2yz5 + 15x3z3
we know that
27-------------> 3³
15-------------> 3*5
z^5-----------> z² * z³
x³------------> x² * x
substituting in the original expression<span>
−27x2yz5 + 15x3z3---------->[-3</span>³*x²*y*z³*z²]+[3*5*x²*x*z³]
[-3³*x²*y*z³*z²]+[3*5*x²*x*z³]-------> [3*x² *z³]*{[-3² *y*z²]+[5*x]}
the greatest common factor is [3*x² *z³]
