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telo118 [61]
3 years ago
12

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg. How many toys did

Oleg have?
PLS ANSWER ASAP AND SHOW YOUR WORK! Thank you so much :p
Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

x + y + z = 600

x + 2x + x + 40 = 600

4x + 40 = 600

Subtract 40 on both sides

4x =  600 - 40

Divide by 4 on both sides

x = \frac{560}{4} = 140

Oleg had 140 toys

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