Question

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg. How many toys did Oleg have?
PLS ANSWER ASAP AND SHOW YOUR WORK! Thank you so much :p

Answer 1

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

$x + y + z = 600$

$x + 2x + x + 40 = 600$

$4x + 40 = 600$

Subtract 40 on both sides

$4x = 600 - 40$

Divide by 4 on both sides

$x = \frac{560}{4} = 140$

Oleg had 140 toys