Is this correct ? (Prime Factor Q) Thanks.

Please help me I really need help with this

Helga [31]

Answer:

The answer might be c

Step-by-step explanation:

4 0

3 years ago

Mathew deposits 400800.00 kina with the bank which offers 5½% interest per annum. calculate the interest earned after four years

Sati [7]

Solution

For this case we can use the following formula:

$A=P(1+\frac{r}{n})^{nt}$

Where:

P= 400800 = present value

A= future value

r= 0.055 interest rate

n= 4, number of times that the interest is compund in a year (quarterly)

t= 4 years

Replacing we got:

$A=400800(1+\frac{0.055}{4})^{4\cdot4}=498679.58$

then the interest would be:

$I=A-P=498679.58-400800=97879.58$

4 0

1 year ago

Your favorite stock opened the day's trading at $44.17 per share. When trading closed for the day, your stock was priced at $38.

Masja [62]

Answer:

$835.20

Step-by-step explanation:

First you need to find out how many profit you had at first by multiplying 145 and $44.17.

So, 145*$44.17 = 6404.65

Then find out how much profit you had after it decreased by multiplying 145 and $38.41.

So, 145*$38.41 = 5569.45

Now to find how much profit you lost, you have to subtract $6,404.65 and $5,569.45.

$6,404.65 - $5,569.45 = $835.20

4 0

3 years ago

A movie theater decreased the size of its popcorn bags by 20%. If the old bags held 15 cups of popcorn, how much do the new bags

vovikov84 [41]

Answer:

Your answer will be  $12$  cups of popcorn.

Step-by-step explanation:

To find out how much the new bags hold, you need to find out the discount.

$\frac{20}{100 } = .2$

$15 * .2 = 3$

We know that the discount is $3$ .

To figure out how much the new bags hold, subtract by the old bags.

$15 - 3 = 12$

The new bags hold 12 cups of popcorn. 

7 0

3 years ago

The national average for the number of students per teacher for all U.S. public schools in 15.9. A random sample of 12 school di

Nady [450]

Answer:

The 95% confidence interval for the true mean number of students per teacher is (17.9, 20.5). The lower bound of the interval is above the national average, which means that this estimate is higher than the national average.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 12 - 1 = 11

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 11 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.201

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.201\frac{\sqrt{4.41}}{\sqrt{12}} = 1.3$

In which s is the standard deviation of the sample(square root of the variance) and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 19.2 - 1.3 = 17.9 students.

The upper end of the interval is the sample mean added to M. So it is 19.2 + 1.3 = 20.5 students

The 95% confidence interval for the true mean number of students per teacher is (17.9, 20.5). The lower bound of the interval is above the national average, which means that this estimate is higher than the national average.

5 0

3 years ago