If 0.5 L of solution contains 4 mol
then let 1 L of solution contain x mol
⇒ (0.5 L) x = (4 mol) (1 L)
x = (4 mol · L) ÷ (0.5 L)
x = 8 mol
Thus the molarity of the Sodium Chloride solution is 8 mol / L OR 8 mol/dm³.
Answer:
a lot but im pretty sure if u just take avogadros number and multiply it by 9.8 u get the answer
Explanation:
Explanation:
(Ques- A) Why does the first method for determining volume work only for a regular-shaped object?
<u>(Ans- A)</u> <em>Because the method requires precise dimensions of objects for result, which is not possible for irregular shaped objects.</em>
(Ques - B) Will the second method for determining volume work for any object or just an odd-shaped one? Why?
<u>(Ans-B)</u> <em>It will work for both regular and irregular shaped objects since both displace equal volumes of water.</em>
(Ques - C) Is one method of measurement more accurate than the other? Why or why not?
<u>(Ans-C)</u> <em>Both are pretty accurate, with some experimental errors which may creep in accidentally. </em>
(Ques- D) Would the displacement method of measurement work for a cube of sugar? What about a cork? Why?
<u>(Ans - D)</u> <em>No, the method would not work because sugar being soluble, will dissolve in water. </em>
<em>No, the method would not work because sugar being soluble, will dissolve in water. Cork is less dense than water so floats on it, with only part of it submerged in water, resulting in displacement of less volume of water than actual volume of Cork.</em>
(Ques-E) What did you find out from this investigation? Be thoughtful in your answer.
<u>(Ans- E)</u> <em>I learnt about determining volume of different objects from this investigation. </em>(Sorry, I know its not a very thoughtful answer)
Answer:
The pH of a solution with the [H + ] = 1 × 10 -2 M is 2 and the pH of a solution with the [H + ] = 1 × 10 -10 M is 10. ( I think this is correct ).
Explanation:
Answer:
0.720 M/s
Explanation:
Let's consider the following balanced equation.
5Br⁻(aq) + BrO⁻₃(aq) + 6H⁺(aq) → 3 Br₂(aq) + 3H₂O(l)
The molar ratio of Br⁻ to Br₂ is 5:3, that is, when 5 moles of Br⁻ are consumed, 3 moles of Br₂ are produced. If the average rate of consumption of Br⁻ is 1.20 × 10⁻⁴ M/s, the average rate of formation of Br₂ is:
