5. What plate boundary could form a mountain chain of sedimentary rock?

When solid ammonium carbamate sublimes, it dissociates completely into ammonia and carbon dioxide according to the following equ

Harlamova29_29 [7]

Answer: The equilibrium constant for the given equation is 0.0315

Explanation:

We are given:

Total pressure in the container = 0.596 atm

The given chemical equation follows:

$N_2H_6CO_2(s)\rightleftharpoons 2NH_3(g)+CO_2(g)$

Initial: -

At eqllm: - 2x x

Evaluating the value of 'x'

$\Rightarrow (x+2x)=0.596\\\\x=0.199$

The expression of $K_p$ for above equation follows:

$K_p=p_{CO_2}\times (p_{NH_3})^2$

The partial pressure of pure solids and pure liquids are taken as 1 in the equilibrium constant expression.

Putting values in above expression, we get:

$K_p=(0.199)\times (2\times 0.199)^2\\\\K_p=0.0315$

Hence, the equilibrium constant for the given equation is 0.0315

7 0

3 years ago

What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?

zysi [14]

Answer: -

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[ $\left[\begin{array}{cccc}concentrations&HNO2&H+&NO2\\Initial&2.00&0&0\\Change&-x&+x&+x\\Equilibrium&2.00-x&x&x\end{array}\right]$

Ka = $\frac{x2}{2.00-x}$

5.00 x 10-6 = $\frac{x2}{2.00-x}$

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

6 0

3 years ago

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

Answer: The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

Explanation:

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

What statement would beast describe a digital signal

Assoli18 [71]

Best* and are there answer choic

6 0

4 years ago

650.0 mL of a gas is under a pressure of 840.0 torr. What would the volume of

zheka24 [161]

Answer:

Explanation:using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?

6 0

2 years ago