Answer:
2.51 x 1023 atoms C
Explanation:
MW C = 12.011
5g x (1mol/12.011g) =0.416 mol
0.416 mol x (6.022x10^23) = 2.51 x 1023 atoms C
Hello!
the correct setup is shown at bottom of your question
we get
total moles*(1/102.0 g/mol)= total grams Al2O3
hope this helps. any questions please ask. thank you kindly
Hello!
If there's an air bubble inside the buret, and the bubble escapes the buret during the titration the initial volume lecture (Vi) would be lower (closer to 0) than the actual one, and the recorded consumed volume (ΔV=Vf-Vi) would be higher than the actual one and thus the calculated concentration of the hydrochloric acid would be higher than the real one.
Have a nice day!
turns red litmus paper because it is a acid
