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SpyIntel [72]
3 years ago
8

Can you guys tell me what does C , A, and B equal

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

you will need to use the law of cosines since this picture does not indicate that this is a right triangle

c^2 = a^2 + b^2 – 2ab cos C,

16^2 = 17^2+8^2 -2*17*8*cosC

256=289-272cosC

-33=-272cosC

33/272 = cosC

cos^-1 (33/272)=C  taking the inverse cos

C=83.0  (to the nearest tenth)

b^2 = a^2 + c^2 – 2ac cos B,

8^2 = 17^2 +16^2 -2*17*16cosB

64=289-544cosB

-225=-544cosB

225/544=cosB

cos^(-1) =B

B=65.5

A=180-83-65.6

A=31.4

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If a + b = -6 and x + y + z = -2, what is 8a - 7x - 7z - 7y + 8b
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Answer:

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Step-by-step explanation:

a + b = -6

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We want 8a so multiply the first equation by 8

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We also want -7x so multiply the second equation by -7

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Add the two equations together

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-7x-7y-7z = 14

-------------------------

8a+8b-7x-7y-7z = -34

Rearranging the order

8a - 7x - 7z - 7y + 8b = -34

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