Question

Can you guys tell me what does C , A, and B equal

Answer 1

you will need to use the law of cosines since this picture does not indicate that this is a right triangle

c^2 = a^2 + b^2 – 2ab cos C,

16^2 = 17^2+8^2 -2*17*8*cosC

256=289-272cosC

-33=-272cosC

33/272 = cosC

cos^-1 (33/272)=C  taking the inverse cos

C=83.0  (to the nearest tenth)

b^2 = a^2 + c^2 – 2ac cos B,

8^2 = 17^2 +16^2 -2*17*16cosB

64=289-544cosB

-225=-544cosB

225/544=cosB

cos^(-1) =B

B=65.5

A=180-83-65.6

A=31.4