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Archy [21]
3 years ago
5

Just how much is a million?

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0
Hey You!

1 million = 1,000,000

In other words, 1 million is 1000 1000s.
Gnom [1K]3 years ago
5 0
1 million is 7 0's 
1 million is 1000 1000's
1 million is 1,000,000

If this was the appropriate answer make sure to mark as brainliest!
-procklown
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A circle has a radius of 7 cm. Workout the area of the circle. Give your answer correct to three significant figures.
anastassius [24]

Answer:

πr²=22/7×49

=22×7

=154

hope it helps

Mark me brainliest

5 0
2 years ago
What is the answer to 81.56 + n - 2.55
Anna71 [15]
81.56+n-2.55=0
81.56+n=2.55
n=2.55-81.56
n=-79.01
5 0
3 years ago
Read 2 more answers
ΔABC is a right triangle in which is a right angle, AB = 1, AC = 2, and BC = .
ollegr [7]
We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732

The answer for the length of BC is 1.732 units.
8 0
3 years ago
What categories does the the following number belong in? -17
Kipish [7]

Answer:

c.

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5 0
3 years ago
A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol
Phoenix [80]

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

4 0
3 years ago
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