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VARVARA [1.3K]
3 years ago
13

Find y prime if arctan(xy) = 1 + (x^2*y)

Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0
I'm pretty sure that these tips which I give you will make you able to sort things out.
According to the fact that <span>derivative of the function f(x) = y, you an use these formulae in order to calculate the needed result : </span>arctan(xy) = 1+ x^2*y =\ \textgreater \  xy = tan(1+x^2y)
y + xy' = sec^2(1+x^2y)(2x*y + y'*x^2)
Do hope this will lead you to the corect answer! Regards.
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Range [0, infinity)
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You're given a side length of 7 centimeters. How many equilateral triangles can you construct using this information?
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Answer:

One

Step-by-step explanation:

An equilateral triangle has equal side lengths.

With the given information, you can construct one equilateral triangle, with the sides measuring 7cm each.

The sides of the equilateral triangle can't be mixed up, they must stay the same.

Hope this helps.

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3 years ago
A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i
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Answer:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

\hat p=\frac{36}{100}=0.36 estimated proportion of people who take R supplement

p_o=0.39 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:  

Null hypothesis:p=0.39  

Alternative hypothesis:p \neq 0.39  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

8 0
3 years ago
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