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VARVARA [1.3K]
3 years ago
13

Find y prime if arctan(xy) = 1 + (x^2*y)

Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0
I'm pretty sure that these tips which I give you will make you able to sort things out.
According to the fact that <span>derivative of the function f(x) = y, you an use these formulae in order to calculate the needed result : </span>arctan(xy) = 1+ x^2*y =\ \textgreater \  xy = tan(1+x^2y)
y + xy' = sec^2(1+x^2y)(2x*y + y'*x^2)
Do hope this will lead you to the corect answer! Regards.
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X+y=5<br> x^y+y^x=17<br> solve for the value of y and x
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X = 2 
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<span>2 + 3 = 5 </span>
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<span>------------------- </span>

<span>BUT: </span>

<span>x + y = 5 </span>
<span>x^y + y^ x = 17 </span>

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What is the volume of a cylinder with a diameter equal to 6 and height equal to 8? Let pi = 3.14.
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3 years ago
In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, &amp; KM = 3x + 23, find x &amp; the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

               = 45 + 23

               = 68

KL = 9x - 40

    = 9(15) - 40

    = 135 - 40

    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

7 0
3 years ago
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