Ask question

Ask question

All categories

2 years ago

14

Clara has a lawn in front of her house as mapped on the coordinate plane. She wants to plant a bed of flowers between the points

P and Q. Find the length of the bed of flowers. Question 2 options: A) 2 units B) 7 units C) 13 units D) 8 units

1 answer:

Ronch [10]2 years ago

3 0

Answer:

Look Below In the Explanation

Step-by-step explanation:

Point P has coordinates of (4,4) and point Q has coordinates of (4,-4).

Since both points have the same x-coordinates we can subtract point Q's y-coordinate from point P's y-coordinate.

I will set the equation up and try and figure this part by yourself. I hope you learned what to do from previous questions that are very similar to this that I answered.

4 - ( -4) = length of the bed of flowers

Hope that helps and maybe earns a brainliest!

Have a splendid day! :^)

You might be interested in

Formula for finding the line of symmetry of a quadratic function?

padilas [110]

It is the line of symmetry of a parabola and divides a parabola into two equal halves that are reflections of each other about the line of symmetry. It intersects a parabola at its vertex. It is a vertical line with the equation of x = -b/2a.

6 0

3 years ago

Read 2 more answers

Please Help, 20 points and brainiliest, URGENT.

ch4aika [34]

Answer:

Step-by-step explanation:

∠ACB and ∠ECD are vertical angles, so ∠ACB = ∠ECD.

∠D = ∠B

∠A = ∠E

△ABC and △EDC are similar because they have the same angles.

4 0

3 years ago

What is x in 5x +(3-1)=12

olga2289 [7]

Answer:

x=2

Step-by-step explanation:

5x +(3-1) =12

5x +2 =12

5x =12-2

5x =10

x =10÷5

x =2

5 0

2 years ago

Find mPMA + mCMT. Please help..

juin [17]

PMA = 37

CMT = 101 - 54 =47

Total = 37 + 47 = 84

Answer: A. 84

8 0

2 years ago

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago