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lara [203]
4 years ago
6

What is the x-value of the solution of the system of

Mathematics
1 answer:
Nady [450]4 years ago
8 0

Answer:

x = -1, y = -4

Step-by-step explanation:

Let's solve our system of equations by substitution.

y = 5x + 9y = −x + 3

Step: Solve = 5x + 9 for y:

y = 5x + 9

Step: Substitute 5x + 9 for y in y = −x + 3:

y = −x + 3

5x + 9 = −x + 3

5x + 9 + x = −x + 3 + x (Add x to both sides)

6x + 9 = 3

6x + 9 + −9 = 3 + −9 (Add -9 to both sides)

6x = −6

6x/ 6 = −6/6(Divide both sides by 6)

x = −1

Step: Substitute −1 for x in y = 5x + 9:

y = 5x + 9

y = (5)(−1) + 9

y = 4(Simplify both sides of the equation)

So our answers are y = -4 and x = -1.

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9 students in the class play in the school band. 

30% of 30
Well, when doing a percentage you first turn the percentage into a decimal (move the % two units to the left). So 30% = 0.3

In math, the word of  means multiplication, so: 0.3 x 30 
Which equal 9. 

You can also turn the percentage into a fraction, it's really up to preference. 

30/100 of 30 = 3/10 of 30 = 3/10 x 30 = 3/10 x 30/1 = 9/1 or 9

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3 years ago
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3 years ago
Which graph represents a function
Oduvanchick [21]

Answer:

A

Step-by-step explanation:

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8 0
4 years ago
Cylinder height of 7 and a radius of 4 cm. How many cubic centimeters of fluid can fill this cylinder
Alex Ar [27]

Answer:

112π = 351.86 cubic centimeters of fluid to fill the cylinder

Step-by-step explanation:

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4 0
3 years ago
A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
IrinaK [193]

Answer:

a. [ 0.454,0.51]

b. 599.472 ~ 600

Step-by-step explanation:

a)

Confidence Interval For Proportion

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))

x = Mean

n = Sample Size

a = 1 - (Confidence Level/100)

Za/2 = Z-table value

CI = Confidence Interval

Mean(x)=410

Sample Size(n)=850

Sample proportion = x/n =0.482

Confidence Interval = [ 0.482 ±Z a/2 ( Sqrt ( 0.482*0.518) /850)]

= [ 0.482 - 1.645* Sqrt(0) , 0.482 + 1.65* Sqrt(0) ]

= [ 0.454,0.51]

b)

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)

Z a/2 at 0.05 is = 1.96

Samle Proportion = 0.482

ME = 0.04

n = ( 1.96 / 0.04 )^2 * 0.482*0.518

= 599.472 ~ 600

8 0
3 years ago
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