But your answer would be 25 ounces i hope this helps
Answer:
k - 11
Step-by-step explanation:
Answer:
a. 
b. 
Step-by-step explanation:
Theoretical probability is what we expect to happen and experimental probability is what actually happens.
a. In theoretical probability, it doesn't matter what happened in the past. So basically we want to know the probability of rolling a 3 when a number cube is rolled.
There are 6 faces (from 1 to 6) in a number cube. And there is 1 "3". So the probabilty of rolling a 3 is:
1/6
b. In experimental probability, we need to know what happened before. When the cube was rolled 450 times, it came up "3", 67 times.
Hence the experimental probabilty of rolling a "3" is:
67/450
Answer: A
Step-by-step explanation:

Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
_____
<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9