Question

EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

Answer 1

We can calculate the side length with this formula:
4 • Side² = Long Diagonal² + Short Diagonal²
4 • Side² = 16² + 12²
4 • Side² = 256 + 144
4 • Side² = 400
Side² = 100
Side = 10

Source:
http://www.1728.org/quadltrl.htm

Answer 2

Answer

= 10

Explanation

EG is one of the diagonals of the rhombus and the other diagonal is FH.

EG = 16 and FH = 12

The diagonals of a rhombus meet at 90°

From this information we can form a right triangle with legs (16/2)=8 and (12/2)=6

The hypotenuse of this triangle is the side of the rhombus.

Using the pythagorean theorem;

L² = 6²+8²

Where L is the length of the rhombus.

L² = 6²+8²

L = √36+64

= √100

= 10