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kotykmax [81]
3 years ago
10

EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

Mathematics
2 answers:
natulia [17]3 years ago
7 0
We can calculate the side length with this formula:
<span>4 • Side² = Long Diagonal² + Short Diagonal²
</span><span>4 • Side² = 16² + 12²
</span><span>4 • Side² = 256 + 144
</span><span>4 • Side² = 400
</span><span>Side² = 100
</span>Side = 10

Source:
http://www.1728.org/quadltrl.htm



Tom [10]3 years ago
4 0

<u>Answer</u>

= 10


<u>Explanation</u>

EG is one of the diagonals of the rhombus and the other diagonal is FH.

EG = 16 and FH = 12

The diagonals of a rhombus meet at 90°

From this information we can form a right triangle with legs (16/2)=8 and (12/2)=6

The hypotenuse of this triangle is the side of the rhombus.

Using the pythagorean theorem;

L² = 6²+8²

Where L is the length of the rhombus.

L² = 6²+8²

L = √36+64

= √100

= 10

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Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
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Marat540 [252]

Answer:

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Step-by-step explanation:

First Multiply the number outside of the brackets with the numbers inside the brackets. Ex:3 x 3x and 3 x -y

17y-2x+3(3x-y)+2x

That should get you to this.

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Next combine like terms.

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Hope this helps!

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KATRIN_1 [288]
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in your equation x² + 11x + 7 ... a = 1, b = 11, and c = 7. what you do is you take the coefficients of every term, then plug it into your equation:
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not pretty, i know. but, regardless, you can simplify it:
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they look confusing, but those are your two factors. they can be simplified just slightly by changing the signs in the middle due to the -11:

(x + (11 + √93)/2) (x - (11 - √93)/2)

and how these would read, just in case the formatting is too confusing for you: x plus the fraction 11 + root 93 divided by 2. the 11s and root 93s are your numerator, 2s are your denominator.
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