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2 years ago

PLEASE HELP ME, IF CORRECTLY ANSWERED I’LL GIVE BRAINLIEST

Mathematics

2 answers:

cricket20 [7]2 years ago

8 0

Answer:

C=1

Step-by-step explanation:

Put the first point in the equation y=ax^2+bx+c where x=0 and y=1 you get

1=a*0+b*0+c

1=c

Vedmedyk [2.9K]2 years ago

7 0

Answer:

c=f(x)−ax^2−bx

Step-by-step explanation:

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An irrational number between -2 and -1<br><br> a rational number between -2 and -1

leva [86]

Answer:

An irrational number between -2 and -1 would be $\frac{-\pi }{2}$

A rational number between -2 and -1 would be -1.5

Step-by-step explanation:

$\frac{-\pi }{2}$ = -1.570796... This number does not have repeating decimals, patterns, and it isn't a terminating decimal. It is irrational.

-1.5 is a terminating decimal, therefore it is rational, as well as between -2 and -1.

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1 year ago

Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has

MrMuchimi

The answer to this question is C

8 0

2 years ago

Read 2 more answers

please look at the problem and help. I tried to ask my teacher for help earlier but she ignored me so please don't ignore this.

Alchen [17]

36*40+36*40-6*6=2844ft^2

we had to subtract the area of the closet so it wasn't counted twice :P

8 0

2 years ago

Help with matrices please? Any wrong/not applicable answers will be reported and BLOCKED

marin [14]

m x H = $\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]$

Step-by-step explanation:

Step 1; Multiply 5 with this matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get a matrix $\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]$

Multiply the fraction $\frac{2}{5}$ with the matrix $\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]$ and we get $\left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]$

Step2; Now equate corresponding values of the matrices with each other.

-5 = $\frac{-2m}{5}$ and so on. By equating we get the value of m as $\frac{25}{2}$

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get $\left[\begin{array}{ccc}2&9&-9\\\end{array}\right]$ .

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

$\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]$ . Equating the matrices from step 3 and 4 we get the value of H as $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 5; Now to find the value of m x H we need to multiply the value of $\frac{25}{2}$ with the matrix $\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]$

Step 6; Multiplying we get the matrix m x H = [ -25 $\frac{75}{2}$ $\frac{-25}{2}$ ]

8 0

2 years ago

Is there a math person who could give a hand

Gnesinka [82]

Answer:

I believe that the answer is D.

Step-by-step explanation:

Hope this helps!

4 0

2 years ago