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Alexus [3.1K]
3 years ago
12

PLEASE HELP ME, IF CORRECTLY ANSWERED I’LL GIVE BRAINLIEST

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0

Answer:

C=1

Step-by-step explanation:

Put the first point in the equation y=ax^2+bx+c where x=0 and y=1 you get

1=a*0+b*0+c

1=c

Vedmedyk [2.9K]3 years ago
7 0

Answer:

c=f(x)−ax^2−bx

Step-by-step explanation:

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Quadrilateral KLMN is similar to quadrilateral OPQR. Find the measure of side QR.
Shalnov [3]

Answer:   12.6=13

Step-by-step explanation:

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2 years ago
What number has the square root that lies between 8 and 9?
devlian [24]

Step-by-step explanation:

So, √69 is between 8 and 9 . Since 69 is much closer to 64 than to 81 , the best whole number estimate is 8

8 0
3 years ago
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An apple crisp recipe calls for 90 grams of white sugar and 55 grams of brown sugar. How many kilograms of sugar, including both
denis-greek [22]
90 grams are equivalent to 0.09 kilograms and 55 grams are equivalent to 0.055.
So 0.09 + 0.055 = 0.145.
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3 years ago
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Help plss, i need to know this answer right now!
Aleksandr [31]

Answer:

50

Step-by-step explanation:

totally guessing just seems logical

4 0
2 years ago
Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)
Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = \frac{1}{2}(AD+BC)

By using expression for the length of a segment between two points,

Length of a segment = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between two points A(-5, -6) and D(3, 2),

AD = \sqrt{(3+5)^2+(2+6)^2}

AD = \sqrt{64+64}

AD = \sqrt{128}

AD = 8\sqrt{2}

Distance between B(-6, -2) and C(-4, 0)

BC = \sqrt{(-6+4)^2+(-2-0)^2}

BC = \sqrt{8}

BC = 2\sqrt{2}

Therefore, m(YZ) = \frac{1}{2}(8\sqrt{2}+2\sqrt{2})

                             = \frac{1}{2} (10\sqrt{2})

                             = 5\sqrt{2}

Option C will be the answer.

7 0
2 years ago
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