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4 years ago

What is the domain of the function y= _X+6 - 7?

Mathematics

2 answers:

Tresset [83]4 years ago

4 0

Answer:

we know that

The radicand of the function must be greater than or equal to zero

the solution is the interval---------> [-6,∞)

therefore

the answer is

The domain are all values of x greater than or equal to minus six

WITCHER [35]4 years ago

3 0

Here’s your answer. {x|x>-6. I think this is it I’m not sure tho

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The diagram below shows how much time Antoine spends doing different activities each day. How many hours does Antoine sleep in a

Harman [31]

Your missing the diagram. Thus, I will try my best to help

Answer/Step-by-step explanation:

Given;

The diagram below shows how much time Antoine spends doing different activities each day.

How many hours does Antoine sleep in a day?

Solve;

To find how many hours does Antoine sleep in a day;

24 hour × percent of hour sleep = Hours sleep in a day

The sleeping hours = 24h × % = Hour

<u>If you still do not understand please shown the diagram!</u>

<em>~Learn with Lenvy~</em>

8 0

2 years ago

Could anyone tell me the answer of this question?<br>Pls answer fast

jarptica [38.1K]

Answer:

28.

Step-by-step explanation:

A = bh = 8 · 3.5 = 28

3 0

3 years ago

Read 2 more answers

Which are the correct reprsentives of the inequality -3(2x-5)<5(2-x)check all that apply x<5

a_sh-v [17]

Answer:

Step-by-step explanation:

$-3(2x-5)$

3 0

4 years ago

Suppose that T : R3 → R2 is given by:

Ad libitum [116K]

Answer: The required answers are

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is $\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

Step-by-step explanation: We are given a linear transformation T : R³ → R² defined as follows :

$T(a,b,c)=(a,b).$

We are to

(a) prove that T is a linear transformation

and

(b) find a matrix A such that T(x) = Ax.

(a) Let s, t are any real numbers and (a, b, c), (a', b', c') ∈ R³.

Then, we have

$T(s(a,b,c)+t(a',b',c'))\\\\=T(sa+ta',sb+tb',sc+tc')\\\\=(sa+ta',sb+tb')\\\\=(sa,sb)+(ta'+tb')\\\\=s(a,b)+t(a',b')\\\\=sT(a,b,c)+tT(a',b',c').$

So, we get

$T(s(a,b,c)+t(a',b',c'))=sT(a,b,c)+tT(a',b',c').$

Therefore, T is a linear transformation.

(b) We know that B = {(1, 0, 0), (0, 1, 0), (0, 0, 1)} is a standard basis for R³ and B' = {(1, 0), (0, 1)} is a standard basis for R².

So, we have

$T(1,0,0)=(1,0)=1(1,0)+0(0,1),\\\\T(0,1,0)=(0,1)=0(1,0)+1(0,1),\\\\T(0,0,1)=(0,0)=0(1,0)+0(0,1).$

So, the matrix A such that T(x) = Ax will be given by

$\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

Thus,

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is $\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}$

4 0

3 years ago

(x²y−3y²+5xy² )−(−x²y+3xy² −3y² )

KATRIN_1 [288]

Answer:

=2xy²+2x²y

Step-by-step explanation:

Delete the parenthesis of both operations.

= x²y - 3y² + 5xy² + x²y - 3xy² - 3y²

Then you have to make the simplification

= 2xy²+2x²y

6 0

3 years ago