3 carries of 8 yds.....3 * 8 = 24 yds
5 carries of 6 yds.....5 * 6 = 30 yds
so we have a total of 8 carries for 54 yds..
54/8 = 6.75 <== average yds per carry
he solution set is
{
x
∣
x
>
1
}
.
Explanation
For each of these inequalities, there will be a set of
x
-values that make them true. For example, it's pretty clear that large values of
x
(like 1,000) work for both, and negative values (like -1,000) will not work for either.
Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are all the
x
-values that will work for at least one of them. To do this, we solve both inequalities for
x
, and then overlap the two solution set
-3/8 = -0.375
-5/8 = -0.625
-1/8 = -0.125
1/4 = 0.25
<span>0.5 = 0.5
</span>
Therefore 1/4 & 0.5 & -1/8 > -3/8
Hello,
Please, see the attached file.
Thanks
Answer:
4√(xy³)
Step-by-step explanation:
8√(x²y⁶)
The above expression can be simplified as follow:
8√(x²y⁶)
Recall:
m√a = a^1/m
Therefore,
8√(x²y⁶) = (x²y⁶)^1/8
Recall:
(aⁿ)^1/m = a^(n/m)
Therefore,
(x²y⁶)^1/8 = x^(2/8)•y^(6/8)
= x^1/4•y^3/4
= (xy³)^1/4
Recall :
a^1/m = m√a
Therefore,
(xy³)^1/4 = 4√(xy³)
Therefore,
8√(x²y⁶) = 4√(xy³)
