Explain why the polynomial 100x^2 + 150x + 49 is not a perfect square.

1 answer:

4 0

Answer: The correct answer is Choice C.

For this polynomial to be a perfect square, it would need to be:
(10x + 7)^2

This will ensure that the first terms and the last terms will be 100x^ and 49. However, if you use foil to multiply the factors, you will not get 150x for the center term. Choice C also states that 150x will not be the middle term.

You might be interested in

In the diagram below of triangle UVW, X is a midpoint of UV and Y is a midpoint

NeTakaya

Step-by-step explanation:

Given: X is midpoint of UV and Y is midpoint of VW.

$\therefore XY || UW$

(By mid-point theorem)

$\therefore \angle XYV \cong \angle UWY\\.. (corresponding\: \angle 's) \\\therefore m\angle XYV = m\angle UWY\\\therefore 98 - 6x = 63- x\\\therefore 98 - 63= 6x- x\\\therefore 35= 5x\\\\\therefore x = \frac{35}{5}\\\\\huge \orange {\boxed {\therefore x = 7}} \\\\m\angle UWY = (63 - x) °\\\\\therefore m\angle UWY = (63 - 7) °\\\\\huge \purple {\boxed {\therefore m\angle UWY = 56 °}}$

5 0

3 years ago

Which shows the expression x^2-1/x^2-x in simplest form

____ [38]

Answer:

$\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}$

Step-by-step explanation:

$\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}$