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Zinaida [17]
2 years ago
12

A polynomial function g(x) has a zero of 8-5i with multiplicity 4. What is the minimum possible degree of f(x)?

Mathematics
1 answer:
Nikitich [7]2 years ago
8 0
I think it’s B hope it’s right
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Write the equation of the line in slope-intercept form.
Natasha_Volkova [10]

Answer:

y=-1/2x-2

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3
Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

y = 6

Substituting the values into equation (1) and solve c, we have:

60 = c * 5 * 6

60 = c * 30

c = 60 / 30

c = 2

Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0
3 years ago
Pls help as quick as possible 8th grade math!!!!!
Maksim231197 [3]

Answer:

1) y= 3x + 7

2) y= 3/4x + 10

3) y= -5x - 2

4) y= 12x - 6

5) y= 1/2 + 9

Step-by-step explanation:

6 0
2 years ago
Which lengh can be rounded up to the nearest tenth of an inch a. 66.61 b. 5.055 c.4.91 or d. 6.5
Nesterboy [21]
<span>In the given choices, everything can be rounded into nearest tenths.
a. 66.61 – It can be rounded into 66.6
b. 5.055 – it can be rounded into 5.1
c. 4.91 – it can be rounded into 4.9
d. 6.5 – it stays as is.
So everything can be rounded into nearest tenths, however, Letter b. 5.055 is the only one who were rounded up because the number next to tenths value is 5, so the rules of rounding must be followed

</span>



8 0
3 years ago
All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,
Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side l, its diagonal would be l\sqrt{2}, and its area l^2

If the big square has a area of 900, this implies that its side is \sqrt{900}, so the two diagonal of squares 2 and 4 added together would be \sqrt{900}, therefore one diagonal wold be \frac{\sqrt{900}}{2}. and its side \frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}. The area (of one square) is (\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}

finally the two areas combined (squares 2 and 4) would be 225

6 0
2 years ago
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