The nuclear product of radioactive decay is called the
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The question is incomplete. Here is the complete question.
An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.
Answer: v% = 0.21 m/s
Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that: ΔpΔx≥
where h is <u>Planck's constant</u> and it is equal to 6.626.m²kg/s.
Since p (momentum) is p = m.v:
mΔv.Δx ≥
Δv =
Given that: r = x = 1.54.m and mass of an electron is m=9.1.
kg
Δv =
Δv = 0.0376.
As percentage of average speed:
Δv..100% =
.10² = 0.021.10 = 0.21%
The least possible uncertainty in a speed of an electron is 0.21%.
<u>Answer:</u>
<u>For a:</u> Work done for the given reaction is 2477.572 J.
<u>For b:</u> Work done for the given reaction is 0 J
<u>Explanation:</u>
To calculate the work done for the reaction, we use the equation:
Ideal gas equation follows:
Relating both the above equations, we get:
......(1)
where,
= difference in number of moles of products and reactants =
R = Gas constant = 8.314 J/K.mol
T = temperature =
- <u>For a:</u>
The chemical reaction follows:
Putting values in equation 1, we get:
Hence, work done for the given reaction is 2477.572 J.
- <u>For b:</u>
The chemical reaction follows:
Putting values in equation 1, we get:
Hence, work done for the given reaction is 0 J.