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Semmy [17]
3 years ago
7

Ahh, help me I don’t know what to pick

Chemistry
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

for what? is there supposed to be a picture?

Explanation:

??

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2 Zn + 2HNO2-> 2 ZN(NO2)2 + H2
Aliun [14]
It 6.8 so there you go And this answer is Long because I just need points lol
8 0
3 years ago
Calculate the molality of a solution containing 257 g glucose (c6h12o6) dissolved in 1.62 l of water. assume a density of 1.00 g
Alex777 [14]
Molality is defined as the number of moles of solute in 1 kg of solvent.
since density and volume has been given we can calculate the mass of water
mass = density x volume
mass = 1.00 g/mL x 1620 mL = 1620 g
number of moles of glucose - 257 g / 180 g/mol = 1.43 mol
number of moles of glucose in 1620 g - 1.43 mol
therefore number of moles in 1000 g - 1.43 mol / 1.620 kg = 0.883 mol/kg
therefore molality is 0.883 mol/kg
4 0
4 years ago
A female spinach plant with flat (Ff) leaves is crossed with (pollination and fertilization occur) a male spinach plant with cri
Vedmedyk [2.9K]

Answer:

Question

A female spinach plant with flat (Ff) leaves is crossed with (pollination and fertilization occur) a male spinach plant with crinkly (ff) leaves. Explain wha

Explanation:

6 0
3 years ago
A gas mixture at 535.0°C and 109 kPa absolute enters a heat exchanger at a rate of 67.0 m3/hr. The gas leaves the heat exchanger
SVEN [57.7K]

Answer:

the heat rate required to cool down the gas from 535°C until 215°C is -2.5 kW.

Explanation:

assuming ideal gas behaviour:

PV=nRT

therefore

P= 109 Kpa= 1.07575 atm

V= 67 m3/hr = 18.6111 L/s

T= 215 °C = 488 K

R = 0.082 atm L /mol K

n = PV/RT = 109 Kpa = 1.07575 atm * 18.611 L/s /(0.082 atm L/mol K * 488 K)

n= 0.5 mol/s

since the changes in kinetic and potencial energy are negligible, the heat required is equal to the enthalpy change of the gas:

Q= n* Δh = 0.5 mol/s * (- 5 kJ/mol) =2.5 kW

7 0
3 years ago
Why do we feel cold when we touch the iron?
Darya [45]

Heat flows from our body to iron

8 0
2 years ago
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