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Solnce55 [7]
3 years ago
14

Iq scores are normally distributed with a mean of 100 and a standard deviation of 15 if one person is randomly selected what is

the probability that the persons IQ falls between 110 and 130
Mathematics
1 answer:
beks73 [17]3 years ago
4 0

probability that the persons IQ falls between 110 and 130 is 0.2286 .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that 110<X<130 is equal to the blue area under the curve.

Step 2:

Since μ=100 and σ=15 we have:

P ( 110 < X < 130 )=P ( 110−100 < X−μ < 130−100 )

⇒ P ( (110−100)/15< (X−μ)/σ<(130−100)/15)

Since Z = (x−μ)/σ , (110−100)/15 = 0.67 and (130−100)/15 = 2  we have:

P ( 110<X<130 ) = P ( 0.67<Z<2 )

Step 3: Use the standard normal table to conclude that:

P ( 0.67<Z<2 )=0.2286

Therefore, probability that the persons IQ falls between 110 and 130 is 0.2286 .

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B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given:

  • length of swimming pool = 30 m
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Step-by-step explanation:

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