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Lera25 [3.4K]
3 years ago
12

Which powers are listed in order from least to greatest value?

Mathematics
1 answer:
lord [1]3 years ago
6 0
I would go with B i had this question on my test and i got it correct 
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Serjik [45]
Answer- non proportional
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CAN SOMEONE HELP ME WITH THIS?!?!
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Last year, a women's professional organization made two small-business loans totaling $28,000 to young women beginning their own
igor_vitrenko [27]

Answer:

$7,000 at a rate of 7% and $21,000 at a rate of 14%.

Step-by-step explanation:

Let x be amount invested at 7% and y be amount invested at 14%.

We have been given that a women's professional organization made two small-business loans totaling $28,000. We can represent this information in an equation as:

x+y=28,000...(1)

The interest earned at 7% in one year would be 0.07x and interest earned at 14% in one year would be 0.14x.

We are also told that the organization received from these loans was $3,430. We can represent this information in an equation as:

0.07x+0.14y=3,430...(2)

Form equation (1), we will get:

x=28,000-y

Upon substituting this value in equation (2), we will get:

0.07(28,000-y)+0.14y=3,430

1960-0.07y+0.14y=3,430

1960+0.07y=3,430

1960-1960+0.07y=3,430-1960

0.07y=1470

\frac{0.07y}{0.07}=\frac{1470}{0.07}

y=21,000

Therefore, an amount of $21,000 was invested at a rate of 14%.

x=28,000-y

x=28,000-21,000

x=7,000

Therefore, an amount of $7,000 was invested at a rate of 14%.

8 0
3 years ago
Sonali invests 15% of her monthly salary in insurance policies.
strojnjashka [21]

Answer:

₹42,500

Step-by-step explanation:

Let Sonali's monthly income be ₹x

<h2>According to the question </h2>

15\% \:ofx + 55\% \: of \: x + 12750 = x

=  >  \frac{15}{100} x +  \frac{55}{100} x + 12750 = x

=  >  \frac{70}{100} x + 12750 = x

=  > 12750 = (1 -  \frac{70}{100} )x

=  > 12750 = 30x

=  > x =  \frac{12750 \times 10}{3}

=  > 42500

So your answer will be ₹42,500.

3 0
2 years ago
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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
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