Answer: The probability of selecting either a lime or bubble gum followed by a papaya is 425/2209
Step-by-step explanation:
Since, there are four types of items in the jar, namely- lime, papaya, mango and bubble gum that have quantities of 12, 17, 5 and 13 respectively. Before finding the probabilities, we first add up the quantities or number of different items in the jar.
12 + 17 + 5 + 13 = 47 in total.
Since lime is 12 in number, the probability of selecting a lime is = 12/47.
Bubble gums are 13 in number, so the probability of selecting a bubble gum = 13/47.
Then the probability of selecting either a lime or a bubble gum is the addition of the probabilities of selecting a lime and selecting a bubble gum:
= 12/47 + 13/47
= 25/47.
Again, the probability of selecting a papaya is =
number of papaya/total number of items
= 17/47
If the system is with replacement, then the probability of selecting a lime or bubble gum followed by a papaya is:
= Probability of selecting a lime or bubble gum × Probability of selecting papaya
= 25/47 × 17/47
= 425/2209
The probability of selecting a lime or bubble gum followed by a papaya is 425/2209
