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2 years ago

You have a jar of jelly beans in front of you

Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer: The probability of selecting either a lime or bubble gum followed by a papaya is 425/2209

Step-by-step explanation:

Since, there are four types of items in the jar, namely- lime, papaya, mango and bubble gum that have quantities of 12, 17, 5 and 13 respectively. Before finding the probabilities, we first add up the quantities or number of different items in the jar.

12 + 17 + 5 + 13 = 47 in total.

Since lime is 12 in number, the probability of selecting a lime is = 12/47.

Bubble gums are 13 in number, so the probability of selecting a bubble gum = 13/47.

Then the probability of selecting either a lime or a bubble gum is the addition of the probabilities of selecting a lime and selecting a bubble gum:

= 12/47 + 13/47

= 25/47.

Again, the probability of selecting a papaya is =

number of papaya/total number of items

= 17/47

If the system is with replacement, then the probability of selecting a lime or bubble gum followed by a papaya is:

= Probability of selecting a lime or bubble gum × Probability of selecting papaya

= 25/47 × 17/47

= 425/2209

The probability of selecting a lime or bubble gum followed by a papaya is 425/2209

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